Answer:
Step-by-step explanation:
Sum of 1 through 100 = 100×(1+100)/2
Answer:
88
Step-by-step explanation:
5GP= BP
2BNP= GNP
BP+BNP=333
GP+GNP=225
BNP= 333-BP
BNP= 333-5GP
GP= 225-GNP
GP= 225-2BNP
BNP=333-5(225-2BNP)
BNP=333-1125+10BNP
-9BNP=-792
BNP=88
Hope it helps :)
Mark Brainliest if possible.
Answer: for 9 attendees it would cost $18
Step-by-step explanation: First you have to find the unit rate. So for every 7 attendees it costs $14, divide them both by the GCF which is 7. 14÷7=2
7÷7=1
So for every 1 attendee it is $2.
Now to figure out how much it would cost for 9 attendees, figure out what you have to do to 1 to get 9. Multiply it by 9.
And whatever you do to one number you have to do for the other. So $2 • 9 = $18
So for every 9 attendees it costs $18.
Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
