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tangare [24]
3 years ago
8

What is the value of n? Enter your answer in the box. n = cm

Mathematics
2 answers:
dmitriy555 [2]3 years ago
6 0
If two chords intersect each other inside a circle, the products of their segments are equal.

3n = 6*4
3n = 24
n = 24/3
n = 8
jarptica [38.1K]3 years ago
6 0

Answer:

8 is the answer you are looking for

Step-by-step explanation: not needed

You might be interested in
Find the solution(s) of the system of equations:
murzikaleks [220]

The solutions are (0, - 6) ,(7, 8)

The given system of equations is expressed as

y = x² - 5x - 6- - - - - - - - - - - - (1)

y = 2x - 6- - - - - - - - - - - (2)

We would apply the method of substitution by substituting equation 2 into equation 1. It becomes

x² - 5x - 6 = 2x - 6

x² - 5x - 6 = 2x - 6

x² - 5x - 2x - 6 + 6 = 0

x² - 7x = 0

x(x - 7) = 0

x = 0 or x - 7 = 0

x = 7 or x = 0

Substituting x = 0 into equation 2, it becomes

y = 2 × 0 - 6

y = - 6

Substituting x = 7 into equation 2, it becomes

y = 2 × 7 - 6

y = 14 - 6

y = 8

For more information about quadratic equations, visit brainly.com/question/1214333

#SPJ9

7 0
1 year ago
Pls help me solve this please I will give 70 points please help
Mashutka [201]

Answer:

Fraction Form: \frac{2187}{4000000}

Decimal Form: 0.000547

Step-by-step explanation:

=\frac{5}{256} * \frac{3}{5}^1^2 / \frac{3}{5}^5

\frac{3}{5}^1^2/\frac{3}{5}^5=\frac{2187}{78125}

=\frac{5}{256}*\frac{2187}{78125}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}

\frac{5*2187}{256*78125}

\mathrm{Factor\:the\:number:\:}\:78125=5\cdot \:15625

=\frac{5*2187}{256*5*15625}

\mathrm{Cancel\:the\:common\:factor:}\:5

=\frac{2187}{256*15625}

\mathrm{Multiply\:the\:numbers:}\:256\cdot \:15625=4000000

\frac{2187}{4000000}

[RevyBreeze]

5 0
2 years ago
20. Determine the rate of change for the following equation on the given interval.
BigorU [14]
-2<x<3   | *2
-4<2x<6       | +7
3< 2x+7< 13


3<10<13

The answer is C

4 0
3 years ago
Read 2 more answers
to practice for an Ironman competition John swim 0.86 kilometers each day for three weeks how many meters did he swim in those 3
NARA [144]
1 kilometers =1000 meters
0.86km=0.86*1000=860m
John swam 860 meters each day.
1 week = 7 days
3weeks=3*7=21
21*860=18060 m
Therefore he swam 18060 meters in those three weeks.
6 0
3 years ago
Read 2 more answers
Which pair is a solution of the equation? <br> -7x+3y=2
stira [4]

Answer:

7/3

Step-by-step explanation:

5 0
3 years ago
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