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cestrela7 [59]
3 years ago
9

Evaluate the arithmetic series described : 2+(-2)+(-6)+(-10)...,510

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
4 0
It goes -4 each time.
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How do you work out this math problem?? 3x+15-9=2(x+2)
vovangra [49]
3x + 15 - 9 = 2(x +2)
3x + 6 = 2(x +2)
3x + 6 = 2x + 4
3x + 6 - 2x = 2x - 2x + 4
x + 6 = 4
x + 6 -6 = 4 - 6
x = -2
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3 years ago
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Use the definitions and theorems of this section to evaluate and simplify the following expression. Be sure to express answers w
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\bf (b^4)^2\implies b^{4\cdot 2}\implies b^8

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3 years ago
John volunteers at the animal shelter on weekends. One Saturday, John unloaded 27 bags of dog food. Each bag weighed 35 pounds.
romanna [79]

Answer:

945 ounces

Step-by-step explanation:

if you read it closley you will find that if you multiply you will get 945 ounces because all you have to do is multipply.

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3 years ago
Angela needs $60 to buy a series of books, she has saved $24 dollars and plans to work as a babysitter to earn 4 dollars per hou
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60=4x+24
-24. -24
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7 0
3 years ago
Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they
Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276

Number of ways of choosing 3 students From all males

n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220

The probability that all are male of choosing '3' students

P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }

P(E) =  \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0
3 years ago
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