The second term of the given sequence aₙ = -5(n² + 1n) when solved gives us; a₂ = -20
<h3>How to find the nth term of a sequence?</h3>
We are given the formula for a sequence as;
aₙ = -5(n² + 1n)
Where n is the position of the term.
Now, for the first term, we will have;
a₁ = -5(1² + 1(1))
a₁ = -10
The second term of the sequence is;
a₂ = -5(2² + 1(2))
a₂ = -20
Read more about Sequence at; brainly.com/question/6561461
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Rearrange the polynomial:
a^2–2ab+b^2 - c^2
((a-b)(a-b))-c^2
(a-b)^2-c^2
Set x =a-b and y=c. The formula becomes
x^2-y^2
factoring this polynomial, we get
(x+y)(x-y)
Substituting back, we get:
(a+b+c)(a+b-c)
Let’s multiply it out to check:
A^2 -ab ac
- ab B^2 -bc
-ac bc -c^2
Answer:
11 is correct
12 should be 51°
Step-by-step explanation:
15/sin(104) = 12/sin(J)
J = 50.917°
Answer:
-5.36%
Step-by-step explanation:
I'm 100% sure of my answer
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