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3 years ago

8

Mr.varela bought a block of fudge that weighed 3/4 of a pound. He cut the fudge into 2 equal pieces. What was the weight of each

piece of fudge?

1 answer:

OleMash [197]3 years ago

6 0

To do this, multiply 3/4 by 1/2 and you end up with 3/8 lb. or 0.375 lb.

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Tom was driving 20.3 meters per second in a 45 mile per hour zone. Was Tom speeding? Explain using a unit conversion as well as

My name is Ann [436]

Answer:

Tom was speeding.

Step-by-step explanation:

The driving speed of Tom = 20.3 meters per second.

Speed allowed in the zone = 45 miles per hour zone.

Since the unit of speed allowed is given in miles per hour but the speed of tom is given in meters per second. So, first, we have to convert the meter per second into mile per hour then we can compare and find that Tom is speeding or not.

1 mile = 1609.34 meters

1 hour = 3600 second

Now convert 20.3 into mile per hour.

20.3 meters per second. = (20.3 / 1609.34)*3600 = 45.40981 mile per hour.

Since Tom’s speed is more than the allowed speed so he is speeding.

7 0

3 years ago

PLEASE SOLVE!!!! ASAP!!!! Thanks<br><br> 2[(∛8)²+1/8*16]

ehidna [41]

2[(∛8)²+1/8*16]

(∛8)² = (∛8) x (∛8) = (∛64) = 4
1/8 *16 = 16/8 = 2
Total expression = 2 * (4+2)= 12

6 0

4 years ago

Answer for a cookie ;)

Anuta_ua [19.1K]

Answer:

no

Step-by-step explanation:

but i will still take the cookie

4 0

3 years ago

What’s the 5th term is 2,14,98

iragen [17]

$\bold{\huge{\orange{\underline{ Solution }}}}$

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

$\sf{ 2 , 14 ,.... 98 }$
<u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>

<h3><u>Solution </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>

<u>Therefore</u><u>, </u>

$\sf{a1\: or \:1st\: term = 2 }$
$\sf{a2 \:or \:2nd\: term = 14 }$
$\sf{an \:or\: last\: term = 98}$

<u>Here</u><u>, </u>

Common difference of an AP

$\sf{ a2 - a1 }$

$\sf{ = 14 - 2}$

$\sf{ = 12}$

Thus, The common difference is 12

<u>Now</u><u>, </u>

We know that,

$\sf{an = a1 + ( n - 1 )d}$

$\sf{a5 = 2 + ( 5 - 1 )12}$

$\sf{a5 = 2 + 4 × 12}$

$\sf{a5 = 2 + 48}$

$\sf{\red{a5 = 50}}$

Hence, The 5th term of given AP is 50

4 0

2 years ago

Does anybody know this????

jekas [21]

F(x) = 2 * 2 ^x

f(-2) = 2 * 2^-2

f = 0.5

3 0

3 years ago