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Lana71 [14]
3 years ago
14

50 POINTS

Mathematics
1 answer:
Len [333]3 years ago
8 0

Answer: Option 'B' is correct.

Step-by-step explanation:

Since we have given that

P(A) = 0.5

P(B) = 0.5

P(C) = 0.15

P(D) = 0.7

P(E) = 0.15

We need to find the independent events.

When we consider,

P(A∩D) = P(Event A and Event D) = 0.35

and

P(A) × P(D) = 0.7 × 0.5 = 0.35

We get that

P(A∩D)= P(A) × P(D) = 0.35

All other options are not satisfying the conditions of "Independent events".

Hence, Option 'B' is correct.

You might be interested in
What is 3/4(2x+5)=5(x+12)
lina2011 [118]

Answer:

--16 1/14, -225/14 or -16.07

Step-by-step explanation:

3/4(2x+5)=5(x+12)

3x/2+15/4=5x+60

-225/14

4 0
2 years ago
Eduardo and Paul are leaving the same airport in Florida. Eduardo’s flight to Jamaica is 273 miles long. Paul's flight to Hondur
k0ka [10]

Answer:

B. 41.8° is the correct answer

Step-by-step explanation:

We are given that,

Length of Eduardo's flight path = 273 miles

Length of Paul's flight path = 357 miles

Distance between their destinations = 238 miles.

Now, using the law of cosines, we get,

238^2=273^2+357^2-2\times 273\times 357\times \cos \theta

i.e. 56644=74529+127449-194922\times \cos \theta

i.e. 56644=201978-194922\times \cos \theta

i.e. 194922\times \cos \theta=145334

i.e. \cos \theta=0.7456

i.e. \theta=\arccos 0.7456

i.e.  θ = 41.8°

Hence, the angle between their flight paths is 41.8°.

4 0
3 years ago
Select the equation of the line that passes through the point (2,6) and is perpendicular to the line x=4
Sladkaya [172]

Answer:

?

Step-by-step explanation:

dont ask skool questions man

6 0
3 years ago
Assume that a population of 50 individuals has the following numbers of genotypes for a gene with two alleles, B and b: BB = 30,
Andreas93 [3]

Answer:

the frequency of allele B is 0.7 and allele b is 0.3 in population’s gene pool.

Step-by-step explanation:

Allele frequency is how often an allele occurs in a gene pool relative to the other alleles for that gene

<u>Genotype</u>    <u> No. of Individuals</u><u> </u>     <u>No. of Allele </u><u>B</u>   <u>No. of Allele</u><u> b </u>                      

BB                    30                            30*2 =60                   30*0 =0

Bb                     10                            10*1 =10                       10*1=10

bb                     10                             10 *0 =0                      10*2=20

Total                 50                              70                                 30

Total no. of alleles = 70+30 =100

The frequency of allele B :\frac{\text{number of B alleles}}{\text{total number of alleles}}

:\frac{70}{100}

:0.7

The frequency of allele b :\frac{\text{number of b alleles}}{\text{total number of alleles}}

:\frac{30}{100}

:0.3

Hence the frequency of allele B is 0.7 and allele b is 0.3 in population’s gene pool.

6 0
3 years ago
PLEASE HELP ASAP ILL GIVE BRAINLIEST!!
8_murik_8 [283]

Answer:

A

Step-by-step explanation:

We can see that the -5 means that we move 5 unites down

Only A has this option

4 0
3 years ago
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