Answer:
In 5 years the account will be $ 21,549.68.
Step-by-step explanation:
Given that Meg invested $ 16,000 in a savings account, if the annual interest rate is 6%, to determine how much will be in the account in 5 years for quarterly compounding, the following calculation must be performed:
16,000 x (1 + 0.06 / 4) ^ 5x4 = X
16,000 x 1,015 ^ 20 = X
16,000 x 1.34685500 = X
21,549.68 = X
Therefore, in 5 years the account will be $ 21,549.68.
Answer:
Step-by-step explanation:
booom
Complete Question
If the p-value for your test statistic in a test of hypothesis (for example, a t-test, one-tail) is 0.07 and the significance level alpha is set at 0.05, you conclude that:
A
Both hypotheses H0 and H1 can be accepted
B
The null hypothesis H0 cannot be rejected
C
The null hypothesis H0 can be rejected
D
The research hypothesis H1 can be accepted
Answer:
The correct option is B
Step-by-step explanation:
From the question we are told that
The p-value is 
The level of significance is 
Generally given that it is a one tail test then the possible value of
The null hypothesis is 
Here 
is the mean and x is the value
the possible values of the alternative hypothesis is 
Now from the value given we see that the 
hence
The decision rule is
Fail to reject the null hypothesis
Answer:
then Mathew is 59 years 59 years old and Aubrey was just born
<span>n = 11<span>.
Explanation:
Let m be the number of boxes Mark sells and a be the number of boxes Ann sells.
Since Mark sells 10 less than n, m = n-10. Since Ann sells 2 less than n, a = n-2.
Together, they sold n-10+n-2=2n-12 boxes.
We know that they sold less than n boxes, so our inequality would be
2n-12<n.
To solve this, subtract n from both sides:
2n-12-n<n-n; n-12<0.
Add 12 to both sides:
n-12+12<0+12; n<12.
This means there were less than 12 boxes. The next number down is 11; this woks because Mark sold 10 less than n; 11-10=1. Mark sold at least 1 box.
If n=10, however, 10-10=0; this doesn't work, because Mark did sell at least 1 box. </span></span>
