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german
3 years ago
8

The first three steps in determining the solution set of the system of equations algebraically are shown.

Mathematics
2 answers:
jolli1 [7]3 years ago
8 0
Since both are equivalent to y, the equations must be equivalent.
x^2-x-3= -3x+5
x^2+2x-8=0

(x+4)(x-2)=0
x=-4, x=2

Plug the values of x in to either equation
y=-3(-4)+5
y= 12+5
y=17

y= -3(2)+5
y=-6+5
y=-1

Final answer: (-4,17) and (2,-1)
Viktor [21]3 years ago
4 0

Answer:

ayo the answer is C for ED

Step-by-step explanation:

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Find f(b-2) if f(x) = x^2-6x+1
jasenka [17]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The equivalent expression is ~

  • f(b - 2) =  {b}^{2}  - 10b + 17

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

Let's evaluate f(b - 2) ~

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4 0
3 years ago
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uincy uses the quadratic formula to solve for the values of x in a quadratic equation. He finds the solution, in simplest radica
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In this case it is 0, not 2, which was my first and wrong answer





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Please give an explanation on how you got this answerI'm not sure if it's too late or what, but I can't get it.
Alona [7]
Step 1: multiple the second equation by 2 so that you get -1/4 for the coefficient of y, the same as in equation 1
equation 2 multiply by 2: 1/4 x - 1/4 y=38  ..........name this equation 3
subtract equation 1 from equation 3: (1/4 x -1/2 x)=38-10
-1/4 x = 28
x=-112
plug in x=-112 in any of the equation, you will get y=-264
so the answer is A
8 0
3 years ago
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