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2 years ago

identify the similar triangles in the diagram, then sketch them so the corresponding sides and angles have the same orientation.

Mathematics

1 answer:

alexandr1967 [171]2 years ago

6 0

Answer:

Traingle LKJ is similar to triangle LMK is similar to triangle KMJ

Step-by-step explanation:

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A car rental company charges $31 per day to rent a particular type of car, and $0.19 per mile. Juan is charged $59.31 for a one-

snow_lady [41]

x = # of miles

$59.31 = $31 + $0.19x

Subtract $31 from both sides

$28.31 = $0.19x

Divide both sides by $0.19

149 = x

Juan drove 149 miles

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3 years ago

Please I need help immediately

just olya [345]

Answer:

Step-by-step explanation:

4x+6<= -54

4x <= -60

x <= -15 [The point -15 is included, so it must be a solid dot]

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5x + 7 > -18

5x > -25

x > -5 [The point -5 is NOT included, so it should be an empty dot.]

Solution C seems the best.

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2 years ago

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Anettt [7]

Answer:

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3 years ago

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What distance is shorter 3/4 or 2/4

dolphi86 [110]

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3 years ago

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Of the entering class at a college, % attended public high school, % attended private high school, and % were home schoole

Veronika [31]

Answer:

(a) The probability that the student made the Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

A = a student attended public high school

B = a student attended private high school

C = a student was home schooled

D = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

$P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})$

Compute the probability that the student made the Dean's list as follows:

$P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)$

$=(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655$

Thus, the probability that the student made the Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D)}$

$=\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411$

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

$P(C^{c}|D^{c})=1-P(C|D^{c})$

$=1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185$

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

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2 years ago