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meriva
3 years ago
12

Factor by grouping x^3-4x^2+7x-28

Mathematics
1 answer:
Komok [63]3 years ago
5 0

Answer:

(x - 4)(x^2 + 7)

Step-by-step explanation:

x^2 is a factor of the first two terms:  x^3 - 4x^2 = x^2(x - 4).

7 is a factor of the last two terms:  7(x - 4).  

Note how (x - 4) is a factor of the entire four-term expression given above.

Then:   x^3-4x^2+7x-28 = (x - 4)(x^2 + 7)

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Tell whether the ordered pair is a solution to the equation. Please show how you solved it.
Alina [70]

Answer:

The ordered pair is a solution to the equation

Step-by-step explanation:

Plug the ordered pair into the equation as (x,y):

y = -x + 8

4 = -4 + 8

4 = 4

Since both sides are equal to each other, then the ordered pair is a solution to the equation.

6 0
2 years ago
Read 2 more answers
From least to greatest would this be right or do I have to change it?<br><br> 177,156,99,87
harina [27]

Answer:

From least to greatest it would be 87, 99, 156, 177

Step-by-step explanation:

The statement "from least to greatest" means starting from the lowest value and transitioning to the greatest value/

Think of it as least -> greatest.

3 0
3 years ago
The moon is about 240,000 miles from Earth. What is the distance written as a whole number multiplied by a power of ten?
ololo11 [35]

We need to find 240,000 written as a whole number multiplied by a power of ten.

We need to get rid of the four zeros behind 24 in 240,000.

24 would be our whole number.

We would need to multiply 24 by 10,000 to get 240,000.

10,000 is equal to 10^{4} because there are 4 zeros. Ex. when multiplying 200 by 30, we first multiply 2 * 3 then we add 3 zeros to the end of  6. So for 10*10*10*10, we add 4 zeros to the end of 1 which equals 10,000.

So the answer would be 24 × 10^{4}

7 0
3 years ago
Write the equation of a circle with center at (3, -2), which also passes through the point (0, 2).
Airida [17]

\text{The equation of acircle:}\\\\(x-h)^2+(y-k)^2=r^2\\\\(h;\ k)-center\\r-radius\\\\\text{We have center}\ (3,\ -2)\to h=3\ \text{and}\ k=-2.\\\\\text{The radius is the distance between the points} (3,\ -2)\ \text{and}\ (0,\ 2).\\\\\text{The formula of a distance between two points:}\\\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\\text{Substitute:}\\\\d=\sqrt{(2-(-2))^2+(0-3)^2}=\sqrt{4^2+(-3)^2}=\sqrt{16+9}\\\\=\sqrt{25}=5\\\\Answer:\ \boxed{(x-3)^2+(y-(-2))^2=5^2\to\boxed{(x-3)^2+(y+2)^2=25}}

3 0
3 years ago
I need help!
pashok25 [27]

Answer:

No idea sorry we have not learned this yet

6 0
3 years ago
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