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The graph is a circle, centered at the origin, with radius=4.
We know that we can write the equation of a circle with radius r and center (a,b) as :
.
Thus, substituting (a, b) with (0, 0) and r with 4, we have:
.
The solutions of this equation are all the points forming the circle shown in the picture. The solutions of this equation are still the same even if we multiply both sides of the equation by 2, because rewriting the equation as:
,
we would still have the same roots.
Thus, the equation of the circle can be written as :
.
Answer: B
We know that we can write the equation of a circle with radius r and center (a,b) as :
Thus, substituting (a, b) with (0, 0) and r with 4, we have:
The solutions of this equation are all the points forming the circle shown in the picture. The solutions of this equation are still the same even if we multiply both sides of the equation by 2, because rewriting the equation as:
we would still have the same roots.
Thus, the equation of the circle can be written as :
Answer: B
Answer:
Step-by-step explanation:
the formula for calxulating the area if the isosceles triangle is expressed as;
b is the base of the triangle
h is the altitude
Given
b = 16ft
h = 10ft
Substitute
A = 1/2 * 16 * 10
A = 8*10
A = 80ft²
Hence the area of the triangle is 80ft²
b) To get the measure of one side of the triangle, we will use the pythagoras theorem. Let s be the slant side
s² = h²+(b/2)²
s² = 10²+(16/2)²
s² = 10²+(8)²
s² =100+64
s² =164
s = √164
s = 12.8ft
Hence one side of the triangle is 12.8ft