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irinina [24]
3 years ago
5

Hamburgers cost $2.50 and cheeseburgers cost $3.50 at a snack bar. Ben has sold no more than $30 worth of hamburgers and cheeseb

urgers in the first hour of business. Let x represent the number of hamburgers and y represent the number of cheeseburgers. The inequality 2.50x + 3.50y < 30 represents the food sales in the first hour. If Ben has sold 4 cheeseburgers, what is the maximum value of hamburgers Ben could have sold?
Mathematics
1 answer:
Irina18 [472]3 years ago
8 0

Given 2.50x + 3.50y < 30.

Where x represent the number of hamburgers and y represent the number of cheeseburgers.

Now question is to find the maximum value of hamburgers Ben could have sold when he has sold 4 cheeseburgers.

So, first step is to plug in y=4 in the given inequality. So,

2.50x+3.50(4)<30

2.50x+14 <30

2.50x<30- 14 Subtracting 14 from each sides.

2.50x< 16

\frac{2.50x}{2.50} Dividing each sides by 2.50.

x<6.4

Now x being number of hamburgers must be an integer , so tha maximum value of x can be 6,

thus x = 6 hamburgers

So, the maximum value of hamburgers Ben could have sold is 6*2.5=$15

Hope this helps!!

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