What are some words found in geometry that are hard to specifically define

Calculate the slope of a line that goes through the points: (5, 7) & (2, 7). Leave your solution as a simplified (improper)

Fiesta28 [93]

Answer:

0

Step-by-step explanation:

m=(y2-y1)/x2-x1), if m is slope and the 2 points are (x1, y1), (x2, y2).

m=(7-7)/(2-5)

m=0/-3

m=0

also, you don't need to know this but if a line has a slope of zero it's a horizontal line

5 0

2 years ago

Tim has some marbles.

snow_tiger [21]

Answer:

Let x = the number of marbles Tim has

Let 2x = the number of marbles Sue has

x + 2x + 15 = 63

3x = 48

x = 16 marbles

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

I have a box of 24 different types of cup cakes. 1⁄2 of the cupcakes are vanilla. 1⁄8 of the cupcakes are strawberry. And the re

AlexFokin [52]

Answer:

21 7/8 is choclate

1/2 or 2 is vanilla

1/8 is strawberry

Step-by-step explanation:

1/2 x 4 is is 2

1/8 < 2

2 of the cupcakes (into eights) are vanilla from which a dominatorof 8

2 plus 1/8 is 2 1/8

24 - 2 1/8 is 21 7/8

8 0

2 years ago

For a certain drug, the rate of reaction in appropriate units is given by Upper R prime (t )equalsStartFraction 2 Over t plus 1

Tems11 [23]

Answer:

a) 8.13

b) 4.10

Step-by-step explanation:

Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1

In order to get the total reaction R(t) to the drugs at this times, we need to first integrate the given function to get R(t)

On integrating R'(t)

∫ (2/t+1 + 1/√t+1)dt

In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.

∫ (2/t+1 + 1/√t+1)dt

= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt

= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt

= 2ln(t+1) + 2(t+1)^1/2 + C

= 2ln(t+1) + 2√(t+1) + C

a) For total reactions from t = 1 to t = 12

When t = 1

R(1) = 2ln2 + 2√2

≈ 4.21

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

R(12) - R(1) ≈ 12.34-4.21

≈ 8.13

Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.

b) For total reactions from t = 12 to t = 24

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

When t = 24

R(24) = 2ln25 + 2√25

≈ 16.44

R(12) - R(1) ≈ 16.44-12.34

≈ 4.10

Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10

3 0

2 years ago

When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode

yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are central tendency measures in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a normal distribution, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a distribution is not symmetrical, we say it is skewed. The skewness is a measure of the asymmetry of the distribution. In this case, the mean, median and mode are not the same, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (negative skew), or greater than them (positive skew), or approximately equal than the median but much greater than the mode (a variation of a positive skew case).

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a mound-shaped symmetrical distribution, it resembles the normal distribution and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, they are all approximately equal. So, the general relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, considering they have similar characteristics of the normal distribution, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

5 0

2 years ago