Question

Use the grouping method to factor this polynomial x ^ 3 + 2x ^ 2 + 7x + 14

Answer 1

Answer:

B. ($x^{2}$+7)(x+2)

Step-by-step explanation:

The greates common factor between 7 and 14 is 7 so you know that one of the terms is going to be 7....but what times 7 equals 14...2

So we know that in one set of parentheses its going to be (something +2) and in another (something +7)

Well if we know that one is going to be 2, how do we go from 2 to 2$x^{2}$.....2 times $x^{2}$ equals $2x^{2}$

So now we know that one set of parentheses is going to be (something + 2) times ($x^{2}$+7)

So lastly, we have to find out how to get $x^{3}$ but since we already have a $x^{2}$ in the second set of parentheses all we have to do is put a x in the first set because x times $x^{2} = x^{3}$

Hope this helps!