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rosijanka [135]
3 years ago
15

A pulley is used to lift a heavy mass from the floor to the platform. The IMA of the system is 5 and the AMA is 2.5. What is the

efficiency of the system?
Physics
2 answers:
Nuetrik [128]3 years ago
4 0

Answer:

efficiency=\frac{AMA}{IMA}=\frac{2.5}{5}=0.5 or 50%

Explanation:

IMA means Ideal Mechanical Advantage, and it indicates the ratio between the input forces and the output forces without taking into consideration the force needed to overcome friction. In pulleys, this is calculated by counting the number of ropes on the system that in this case is 5

IMA = 5

IMA is greater to the AMA because it doesn't take into consideration friction.

AMA is the Actual Mechanical Advantage, and it is the measure of the usefulness of the pulley, and it indicate the ratio between the output force (Fo) and the input force (Fi). The smaller this ratio, the less useful is the pulley, meaning, it does not simplify the job it is designed to ease, for example, a pulley that does not reduce the force needed to lift a load.

AMA=2.5

So from these two definitions, if we have the actual force ratio and the ideal force ratio, we basically have the "what it is" and the "what could be", a very crude representation of efficiency:

efficiency=\frac{AMA}{IMA}=\frac{2.5}{5}=0.5 or 50%

NemiM [27]3 years ago
3 0
50% as it’s just Ama/ima simple
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Answer:

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Explanation:

From the question we are told that

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               Q =  - Mc_p \Delta T

=>            Q =  -Mc_p (T_m  -  T_c)

Where T_ m  the temperature of metal before immersion

The negative sign show heat lost

The quantity  of gained t by the metal is mathematically represented as      

           Q =  M_o c_o \Delta T

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substituting values

          - 60 * 0.1027 (T_m  - 39)   =   810 * 0.7167 *  (39 - 35)

=>       T_m  =  376.8 ^o C

         

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