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Daniel [21]
2 years ago
9

A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diame

ter1.0 m.
Physics
1 answer:
dalvyx [7]2 years ago
8 0

Complete question:

A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diameter 1.0 m. The ball makes 2.0 revolutions every 1.0 s. What are the magnitude and direction of the acceleration of the ball?

Answer:

The acceleration of the ball is 78.98 m/s², directed inwards

Explanation:

Given;

mass of the ball, m = 175 g

radius of the circle, r = 0.5 m

angular speed of the ball, ω = 2 rev/s

The magnitude of the centripetal acceleration of the ball is calculated as follows;

a_c = \omega^2 r\\\\where;\\\omega \ is \ angular \ speed \ in \ rad/s\\\\a_c = (2\ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} )^2 \times (0.5 \ m)\\\\a_c =78.98 \ m/s^2

The centripetal acceleration is directed inwards.

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Explanation:

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3 years ago
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A tire sits atop a ramp. When the tire is released, it rolls down the ramp. At the ramp's bottom, the speeding tire knocks down
k0ka [10]

Answer:

mechanical energy

Explanation:

Mechanical energy is the combination of both potential energy and kinetic

Mechanical energy can be divided as

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2) potential energy which is the stored energy of position.

Mechanical energy reffered to as

motion energy this energy is responsible for the movement of an object based on its position as well as motion.

Mechanical energy= U + K

Where U= potential energy

K= Kinectic energy

As the tire is sitting on top of a ramp, it posses "potential energy" as it is released and rolls down the ramp the potential is converted to Kinectic energy

4 0
2 years ago
Given the frequency of an electromagnetic wave, what else can you find immediately?
Oksana_A [137]

Answer:

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An electromagnetic waves is produced due to interaction of oscillating electric and magnetic field when they interacts perpendicular to each other. For example, Gamma rays, X rays , ultraviolet rays, visible radiations, infrared rays, micro waves, radio waves.

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3 0
3 years ago
At a certain elevation, the pilot of a balloon has a mass of 120 lb and a weight of 119 lbf. What is the local acceleration of g
Strike441 [17]

Answer:

31.905 ft/s²

Explanation:

Given that

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Weight of the pilot, w = 119 lbf

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Local acceleration of gravity of found by using the relation

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119 = 120 * a/32. 174

119 * 32.174 = 120a

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Therefore, the local acceleration due to gravity at that elevation is 31.905 ft/s²

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