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Otrada [13]
2 years ago
15

A 60.0-kg child takes a ride on a Ferris wheel that rotates four times each minute and has a diameter of 20.0 m. (a) What is the

centripetal acceleration of the child
Physics
1 answer:
IrinaVladis [17]2 years ago
3 0

Answer:

3 because

Explanation:

60÷20=3 ans is this

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A package of aluminum foil contains 50. ft2 of foil, which weighs approximately 6.0 oz. Aluminum has a density of 2.70 g/cm3. Wh
SIZIF [17.4K]

Answer:

1.36 x 10^-3 cm

Explanation:

Area = 50 ft^2 = 46451.5 cm^2

mass = 6 oz = 170.097 g

density = 2.70 g/cm^3

Let t be the thickness of foil in cm.

mass = volume x density

mass = area x thickness x density

170.097 = 46451.5 x t x 2.70

t = 1.36 x 10^-3 cm

Thus, the thickness of aluminium foil is 1.36 x 10^-3 cm.

3 0
2 years ago
The rest deltoid row is a back exercise true or false
bixtya [17]
False because your deltoids are in your shoulders not your back
3 0
3 years ago
Will mark the first answer brainliest. Picture attached, kirchhoffs junction rule!
OLEGan [10]

the neutrons through the nucleus?

Explanation:

7 0
2 years ago
Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular alumin
Alex777 [14]

Answer:

0.92 μC

Explanation:

In a parallel-plate capacitor, the electric field formed is equal to the charge density divited by the vacuum permisivity e0, as there are no dielectric between the plates. e0 is equal to 8.85*10^-12 C^2/Nm^2. The charge density is the total charge of each individual plate divided by its area. Then, the maximum charge allowed will be equal to:

E = \frac{o}{e_0} = \frac{Q}{Ae_0} \\ Q = E*A*e_0 = 3*10^6 N/C * (0.25*\pi *(0.21m)^2)*8.85*10^{-12}C^2/Nm^2 = 9.196 *10^{-7} C

or 0.92 μC

7 0
2 years ago
How strong is the electric field between the plates of a 0.86 µf air-gap capacitor if they are 2.0 mm apart and each has a char
Gala2k [10]
The electric field between the plates is equal to the potential difference across the plates divided by the separation of the plates.
The potential difference across the plates is equal to the charge stored divided by the capacitance.
7 0
2 years ago
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