Answer: 1.65m
Explanation:
Refractive index in terms of the depth of liquid is the ratio of the real depth to the apparent depth of the liquid i.e Refractive index =Real depth/apparent depth
Refractive index of water given = 1.33
Real depth is the measure of how deep is the liquid while apparent depth is the depth at the surface of the liquid.
Real depth = 2.2m
Apparent depth =?
Applying the formula above
Apparent depth =Real depth/refractive index
= 2.2/1.33
= 1.65m
Therefore, the circle of light that exits the surface of the water when that light shines in the middle of the night is 1.65m wide
Answer:2m/s²
Explanation: Well F=MA so sice F=4N and M=2kg let's plug in the values
4N=2KG*A
A=4N/2KG
A=2m/s²
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Answer:
Number of electrons are flowing per second is 2.42 x 10¹⁹
Explanation:
The electric current flows through a wire is given by the relation :
....(1)
Here I is current, e is electronic charge, v is drift velocity of electrons and A is the Area of the wire.
But electric current is also define as rate of electrons passing through junction times their charge, i.e. ,
....(2)
Here N is the rate of electrons passing through junction.
From equation (1) and (2).
But area of wire, 
Here d is diameter of wire.
So, 
Substitute 2.91 x 10⁻³ m for d, 0.000191 m/s for v and 6 x 10²⁸ m⁻³ for n in the above equation.
N = 2.42 x 10¹⁹ s⁻¹
