I’m pretty sure it’s it’s between f and g. Sorry if I’m not exact but hope this helps
Answer:
Therefore, the probability is:
![P=\left(\frac{1}{50}\right)^7\\\\](https://tex.z-dn.net/?f=P%3D%5Cleft%28%5Cfrac%7B1%7D%7B50%7D%5Cright%29%5E7%5C%5C%5C%5C)
Step-by-step explanation:
We calculate the probability that the first 7 keystrokes a monkey types on a typewriter spell Tempest.
We conclude that the word Tempest has a total of 7 letters.
Assume the typewriter has 50 keys.
So the probability for each letter is 1/50.
Therefore, we get:
![P=\frac{1}{50}\cdot\frac{1}{50}\cdot\frac{1}{50}\cdot\frac{1}{50}\cdot\frac{1}{50}\cdot\frac{1}{50}\cdot\frac{1}{50}\\\\P=\left(\frac{1}{50}\right)^7\\\\](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B1%7D%7B50%7D%5Ccdot%5Cfrac%7B1%7D%7B50%7D%5Ccdot%5Cfrac%7B1%7D%7B50%7D%5Ccdot%5Cfrac%7B1%7D%7B50%7D%5Ccdot%5Cfrac%7B1%7D%7B50%7D%5Ccdot%5Cfrac%7B1%7D%7B50%7D%5Ccdot%5Cfrac%7B1%7D%7B50%7D%5C%5C%5C%5CP%3D%5Cleft%28%5Cfrac%7B1%7D%7B50%7D%5Cright%29%5E7%5C%5C%5C%5C)
Therefore, the probability is:
![P=\left(\frac{1}{50}\right)^7\\\\](https://tex.z-dn.net/?f=P%3D%5Cleft%28%5Cfrac%7B1%7D%7B50%7D%5Cright%29%5E7%5C%5C%5C%5C)
Given:
Atul has
lb of candy.
Jose has
lb of candy.
Maria has
lb less than Jose.
To find:
How many more pounds of candy does Atul have than Maria?
Solution:
Since, Maria has
lb less than Jose, therefore
Maria has =
lb
Maria has =
lb
Maria has =
lb
Difference between the candies Atul and Maria have.
Difference =
lb
Difference =
lb
Difference =
lb
Therefore, Atul have
lb of candy more than Maria.
Answer:
Part 1) ![A=36(\pi-2)\ cm^2](https://tex.z-dn.net/?f=A%3D36%28%5Cpi-2%29%5C%20cm%5E2)
Part 2) ![P=6(\pi+2\sqrt{2})\ cm](https://tex.z-dn.net/?f=P%3D6%28%5Cpi%2B2%5Csqrt%7B2%7D%29%5C%20cm)
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
Part 1) Find the area
we know that
The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle
so
![A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B4%7D%5Cpi%20r%5E%7B2%7D-%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29)
we have that the base and the height of triangle is equal to the radius of the circle
![r=12\ cm\\b=12\ cm\\h=12\ cm](https://tex.z-dn.net/?f=r%3D12%5C%20cm%5C%5Cb%3D12%5C%20cm%5C%5Ch%3D12%5C%20cm)
substitute
![A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B4%7D%5Cpi%20%2812%29%5E%7B2%7D-%5Cfrac%7B1%7D%7B2%7D%2812%29%2812%29%5C%5CA%3D%2836%5Cpi-72%29%5C%20cm%5E2)
simplify
Factor 36
![A=36(\pi-2)\ cm^2](https://tex.z-dn.net/?f=A%3D36%28%5Cpi-2%29%5C%20cm%5E2)
Part 2) Find the perimeter
The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle
The circumference of a quarter of circle is equal to
![C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r](https://tex.z-dn.net/?f=C%3D%5Cfrac%7B1%7D%7B4%7D%282%5Cpi%20r%29%3D%5Cfrac%7B1%7D%7B2%7D%5Cpi%20r)
substitute the given values
![C=\frac{1}{2}\pi (12)\\C=6\pi\ cm](https://tex.z-dn.net/?f=C%3D%5Cfrac%7B1%7D%7B2%7D%5Cpi%20%2812%29%5C%5CC%3D6%5Cpi%5C%20cm)
Applying the Pythagorean Theorem
The hypotenuse of right triangle is equal to
![AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm](https://tex.z-dn.net/?f=AC%3D%5Csqrt%7B12%5E2%2B12%5E2%7D%5C%5CAC%3D%5Csqrt%7B288%7D%5C%20cm)
simplify
![AC=12\sqrt{2}\ cm](https://tex.z-dn.net/?f=AC%3D12%5Csqrt%7B2%7D%5C%20cm)
Find the perimeter
![P=(6\pi+12\sqrt{2})\ cm](https://tex.z-dn.net/?f=P%3D%286%5Cpi%2B12%5Csqrt%7B2%7D%29%5C%20cm)
simplify
Factor 6
![P=6(\pi+2\sqrt{2})\ cm](https://tex.z-dn.net/?f=P%3D6%28%5Cpi%2B2%5Csqrt%7B2%7D%29%5C%20cm)
So the question or problem ask to find the equation of a circle which has a center of (-1,2) and a radius of 3 units. To get the equation of the circle, you must first follow the formula which is (x-h)^2 +(y-k)^2 = r^2. So the answer would be letter D. (x+1)2+(y-2)2=9. I hope you are satisfied with my answer