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Alexus [3.1K]
3 years ago
11

Hello, happy Friday, I am just here with some geometry questions.

Mathematics
2 answers:
Butoxors [25]3 years ago
8 0

Answer:

m∠D = 29°

Step-by-step explanation:

First, notice that ΔSTU and ΔDEF are similar triangles.

For instance, for side ST and DE, the scale factor is:

\displaystyle k=\frac{6}{15}=\frac{2}{3}

Likewise, for TU and EF and SU and DF, the scale factor reamins that same:

\displaystyle \frac{10}{4}=\frac{2}{5}\text{ and } \frac{8}{20}=\frac{2}{5}

By SSS Similarity, ΔSTU ~ ΔDEF.

Note that our similarity statement states that ∠S corresponds to ∠D.

So, ∠S = ∠D.

Since the angles remain the same in a scaled factor and ∠S measures 29°, ∠D is also 29°.

stealth61 [152]3 years ago
7 0

Answer:

m<D = 105

Step-by-step explanation:

So, Triangle STU and DEF are similar triangles, because their corresponding side lengths have the same ratio.

For example FD can be multiplied by 2.5 to get SU, and EF can be multiplied by 2.5 to get TU, and ED can me multiplied by 2.5 to get 15.

Anyways, since the two triangles are similar, they have the same angle measures, meaning that angle D can be found by subtracting 46 and 25 from 180 degrees to find the missing angle, which is 105 degrees. I hope that helps.

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Tracy recieves payments of $X at the end of each year for n years. The present value of her annuity is 493. Gary receives paymen
vladimir1956 [14]

Answer:

v = 1/(1+i)

PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493

PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748

PV(G)/PV(T) = 2748/493

{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493

3[1-v^(2n)]/(1-v^n) = 2748/493

Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)

3(1 + v^n) = 2748/493

1 + v^n = 2748/1479

v^n = 1269/1479 ~ 0.858

Step-by-step explanation:

6 0
4 years ago
The velocity V of an object dropped from a tall building is given by V = V64d, where dis
ozzi

Answer:

d = 0.0625 m

Step-by-step explanation:

The velocity of an object dropped from a tall building is given by :

v=\sqrt{64d}

Where

d is the distance in feet

We need to find the distance when the velocity is 32 ft/s

Rearranging for d,

v^2=64d\\\\d=\dfrac{64}{v^2}

Put v = 32 ft/s

d=\dfrac{64}{32^2}\\\\d=0.0625\ m

So, the required distance is 0.0625 m.

5 0
3 years ago
A man is standing at a radar base and observes an unidentified plane at an altitude 6000m flying towards the radar base at an an
liubo4ka [24]

Answer:

The speed in of the plane is 115.47 m/sec

Step-by-step explanation:

Given:

Height at which the plane is flying = 6000 m

Angle of elevation at the radar base = 30 Degrees

Angle of elevation at the radar base after one minute  = 60 Degrees

To Find:

The Speed of the plane in meter per second = ?

Solution:

Let us use the tangent of the angle to find the distance (d) to a point directly below plane:

<u>when the angle is 30 degrees</u>

tan(30) = \frac{6000}{d1}

d1   = \frac{6000}{tan(30)}

d1 = \frac{6000}{0.577}

d1 = 10392.3 meters

<u>when the angle is 60 degrees</u>

tan(60) = \frac{6000}{d2}

d2  = \frac{6000}{tan(60)}

d2  = \frac{6000}{1.732}\\

d2 = 3464.1 meters

<u>distance travelled by aircraft in 1 min is  </u>

=>d1 - d2

=>0392.3 - 3464.1

= 6928.2 m/min

<u>Now converting to m/sec</u>

=>\frac{6928.2}{60}

=>115.47 m/sec

4 0
3 years ago
Which pair of statements describes the end behavior of the graphed function
Alex777 [14]

The statement (A) As x approaches negative infinity, f(x) approaches infinity. As x approaches infinity, f(x) approaches infinity is correct.

<h3>What is polynomial?</h3>

Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.

\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n

We have a polynomial function:

\rm f(x) =  x^{3}+2x^{2}-5x-6

The function is a cubic function and the graph of the cubic function will be a curve.

As we can see in the graph, f(x) grows larger as x approaches negative infinity. f(x) also becomes closer to infinity as x does.

Thus, the statement (A) As x approaches negative infinity, f(x) approaches infinity. As x approaches infinity, f(x) approaches infinity is correct.

Learn more about Polynomial here:

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What's the area of these?
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