Answer: (C) 0.1591
Step-by-step explanation:
Given : A manufacturer of radial tires for automobiles has extensive data to support the fact that the lifetime of their tires follows a normal distribution with


Let x be the random variable that represents the lifetime of the tires .
z-score : 
For x= 44,500 miles

For x= 48,000 miles

Using the standard normal distribution table , we have
The p-value : 

Hence, the probability that a randomly selected tire will have a lifetime of between 44,500 miles and 48,000 miles = 0.1591
If 1295 × p = 714, then you can rearrange the equation to find the percentage.
You have to get p on its own, so you divide 1295 on both sides of the '='.
1295 × p = 714
p = 714 ÷ 1295
p = <span>0.55135135135...
p </span>× 100 = actual percentage
actual percentage = 55.14%
Okay so subtract 50 from both sides and you would get 360=90x and then divide each side by 90 and you would get x= 4 so it took 4 hours
Answer:
(x + 2) ^2 (x - 2) ^ 2 so A is the answer.
Step-by-step explanation: