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Pavlova-9 [17]
3 years ago
11

Mrs.Baca uses a phone card to call her relatives in Colombia.It costs her 45 cents to talk for 15 minutes.How long can she talk

for 75 minutes?
Mathematics
2 answers:
Elis [28]3 years ago
8 0
It will cost Mr. Baca $2.25 to talk for 75 minutes.
zysi [14]3 years ago
6 0
45/15= 3

So 1 minute=3 cents

75*3=225=2.25 converted

75 minutes=$2.25
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On a scale 5 cm is 12 yards. If the length is 30 yards, how many cm is this on the scale?
Scorpion4ik [409]

Answer:

12.5 cm I would believe

Step-by-step explanation:

30 divided by 12 is 2.5, 5 times 2.5 is 12.5

7 0
3 years ago
Complete the recursive formula of the geometric sequence 27,−9,3,−1,
natita [175]

Step-by-step explanation:

a1 = 27

r = -9/27 = -⅓

the formula :

an = a1. r^(n-1)

= 27. (-⅓)^(n-1)

= 3³(-3`¹)^(n-1)

= 3³(-3)^(1-n)

5 0
3 years ago
Find three numbers between -0.55 and -0.54
antoniya [11.8K]
-0.545 , -0.541 , -0.548
3 0
3 years ago
Question 1) Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
USPshnik [31]

Question 1)

Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x

F(G(x)) = 3(2x - 3)^2 + 1

F(G(x)) =3(4x^2 - 12x + 9) + 1

F(G(x)) = 12x^2 - 36x + 27 + 1

F(G(x)) =12x^2 - 36x + 28

Question 2)

Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x

H -1 (x) = x (inverse)

8 0
3 years ago
If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?
eduard

Answer:

cos(\alpha+\beta)=-\frac{84}{85}

Step-by-step explanation:

we know that

cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)

Remember the identity

cos^{2} (x)+sin^2(x)=1

step 1

Find the value of sin(\alpha)

we have that

The angle alpha lie on the III Quadrant

so

The values of sine and cosine are negative

cos(\alpha)=-\frac{8}{17}

Find the value of sine

cos^{2} (\alpha)+sin^2(\alpha)=1

substitute

(-\frac{8}{17})^{2}+sin^2(\alpha)=1

sin^2(\alpha)=1-\frac{64}{289}

sin^2(\alpha)=\frac{225}{289}

sin(\alpha)=-\frac{15}{17}

step 2

Find the value of cos(\beta)

we have that

The angle beta lie on the IV Quadrant

so

The value of the cosine is positive and the value of the sine is negative

sin(\beta)=-\frac{4}{5}

Find the value of cosine

cos^{2} (\beta)+sin^2(\beta)=1

substitute

(-\frac{4}{5})^{2}+cos^2(\beta)=1

cos^2(\beta)=1-\frac{16}{25}

cos^2(\beta)=\frac{9}{25}

cos(\beta)=\frac{3}{5}

step 3

Find cos⁡ (α + β)

cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)

we have

cos(\alpha)=-\frac{8}{17}

sin(\alpha)=-\frac{15}{17}

sin(\beta)=-\frac{4}{5}

cos(\beta)=\frac{3}{5}

substitute

cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})

cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}

cos(\alpha+\beta)=-\frac{84}{85}

4 0
3 years ago
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