Three students want to estimate the mean backpack weight of their schoolmates. To do this, they each randomly chose 8 schoolmates and weighed their backpacks. Then as per the given sample data,
(a) The sample means of the backpacks are: 6.375,6.375,6.625
(b) Range of sample means: 0.25
(c)The true statement is: The closer the range of the sample means is to 0, the less confident they can be in their estimate.
For the first sample, mean= 6.375
For the second sample, mean= 6.375
For the third sample, mean= 6.625
Range of sample means=Maximum Mean- Minimum Mean
= 6.625 - 6.375
= 0.25
The students will estimate the average backpack weight of their classmates using sample means, the true statement is:
The closer the range of the sample means is to 0, the more confident they can be in their estimate.
Learn more about range here:
brainly.com/question/24326172
#SPJ1
Firstly, let's factorise each equation individually - to do this, find 2 numbers that when summed add to the value of the second term, and when multiplied give the value of the third term.
7 and 12 give us 4 and 3 (4+3=7, 4*3=12) -- 8 and 15 give us 5 and 3 (5+3=8, 5*3=15)
Now we can rewrite these equations as (y+4)(y+3) and (y+5)(y+3) respectively.
Putting this in a fraction: (y+4)(y+3)/(y+5)(y+3) -- We can clearly see that there is a y+3 on both sides of the fraction, and given there are no terms outside of the brackets being multiplied, we can directly cancel.
This gives us our final answer:
(y+4)/(y+5)
Answer:A
Step-by-step explanation:
Answer:
B. Perimeter of a square and
C. Side length of a square
Step-by-step explanation:
if n= side length of square then
- Area of square is

- Perimeter of a square is 4×n
- diagonal length of a square is
× n
Thus,
Perimeter of square can be expressed as
×diagonal length of a square
Side length of a square can be expressed as
×diagonal length of a square
but Area of square is
×n×diagonal length of a square
As a Result, Area of square is <em>also dependent of the value n</em>, wheras in other cases it is <em>a proportion of diagonal length of a square</em>
Answer:
Mean = 3640
Mode = 4100
Median = 3830.
Step-by-step explanation:
We are given the following data in the question:
Strength of casts (in psi):
3970,4100,3100,3200,2950,3830,4100,4050,3460
Formula:


Mode is the entry with most frequency. Thus, for the given sample mode = 4100.
Median
Since n = 9 is odd,
Formula:

Data in ascending order:
2950,3100,3200,3460,3830,3970,4050,4100,4100
Median = 5th term = 3830.