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3 years ago

30mL:45mL simplify the ratio

2 answers:

5 0

$30ml:45ml\\\\\dfrac{30}{45}=\dfrac{30:5}{45:5}=\dfrac{6}{9}=\dfrac{6:3}{9:3}=\dfrac{2}{3}\\\\\boxed{30ml:45ml=2ml:3ml}$

dangina [55]3 years ago

4 0

Answer:

2ml : 3ml is the simplified form.

Step-by-step explanation:

We have simplify the given ratio 30ml : 45ml

If we write the ratio in terms of a fraction it becomes like

$\frac{30}{45}$

Now we divide numerator and denominator by 15

we get the new fraction as $\frac{2}{3}$

Therefore the fraction can further be denoted as 2ml : 3ml.

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Single adults: According to a Pew Research Center analysis of census data, in 2012, 20% of American adults ages 25 and older had

netineya [11]

Answer:

B. 50

Step-by-step explanation:

Central limit theorem is used to calculate the sampling distribution of the given case. The number of adults who are 25 years of age or above and not married is 20% of the samples selected. The standard deviation is 0.06 while the sample size should be 50 to conclude the results.

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3 years ago

19. Suppose the diameter of a circle is 10 inches long and a chord is 6 inches long, Find the distance between the chord and the

mihalych1998 [28]

Answer:

10 m

Step-by-step explanation:

x2 + 242 = 262

x2 + 576 = 676

x2 = 100

x = 10

The chord is 10 m from the center of the circle.

3 0

3 years ago

Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into

Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = $(\frac{60\pi }{\pi+4}) in$

b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

b= $\frac{y}{4}$

Area of the square which is L² can now be said to be;

$A_S=(\frac{y}{4})^2 = \frac{y^2}{16}$

On the otherhand; let the radius (r) of the circle be;

2πr = 60-y

$r = \frac{60-y}{2\pi }$

Area of the circle which is πr² can now be;

$A_C= \pi (\frac{60-y}{2\pi } )^2$

$=( \frac{60-y}{4\pi } )^2$

Total Area (A);

A = $A_S+A_C$

= $\frac{y^2}{16} +(\frac{60-y}{4\pi } )^2$

For the smallest possible area; $\frac{dA}{dy}=0$

∴ $\frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0$

If we divide through with (2) and each entity move to the opposite side; we have:

$\frac{y}{18}=\frac{(60-y)}{2\pi}$

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

$y= \frac{240}{\pi+4}$

∴ since $y= \frac{240}{\pi+4}$ , we can determine for the length of the circle ;

60-y can now be;

= $60-\frac{240}{\pi+4}$

= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

also, the length of wire for the square (y) ; $y= (\frac{240}{\pi+4})in$

The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0

3 years ago

The greater of two consecutive EVEN numbers is 40 less than twice the smaller number. Find the larger number

Bas_tet [7]

Answer:

Step-by-step explanation:

z - some integer

2z - first given even integer (the smaller one)

2z+2 - even integer consecutive to 2z (the larger one)

2(2z) - twice the smaller number

2(2z) - 40 - the number 40 less than twice the smaller number

2(2z) - 40 = 2z + 2

4z - 40 = 2z + 2

2z = 42

2z+2 = 42+2 = 44

check:

2(2z)-40 = 2(42)-40 = 84-40 = 44

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3 years ago

April has 5 milligrams of zinc and 0.25 milligrams of copper.

GREYUIT [131]

Answer:

It's 4.75

Step-by-step explanation:

If you subtract 5-.25=? The answer would be 4.75. Hope this helps.

7 0

3 years ago