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Svetradugi [14.3K]
3 years ago
15

The polygons are similar. but they are not necessarily drawn to scale. Find the value of x

Mathematics
1 answer:
Ne4ueva [31]3 years ago
4 0

Answer:

x=9

Step-by-step explanation:

Since the polygons are similar, the ratios of their respective sides are equal.

32/24=(x-1)/6

x-1=8

x=9

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Part A: Xavier needs to collect at least 120 cans for a food drive to earn community service credit. He has already collected 64
Sergeu [11.5K]

Answer:

A

Step-by-step explanation:

He needs to collect at least 120 so if c is what he must still collect

64 +c must be greater than or equal to 120

3 0
2 years ago
Solve the question will mark branliest and with an explantion
erma4kov [3.2K]

Answer:

The car loses $5,635 every year. Multiply 24,500 by 23% (0.23)

5 0
3 years ago
The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true
Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Part A</u>

\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478

<u>Part B</u>

P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767

<u>Part C</u>

\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971

6 0
2 years ago
jennifer scored 75 on her quiz last week. this week she scored 90. what was the percent of increase on the quiz score?
Arlecino [84]

Answer:

The answer is a 20% increase

Hope this helps!

Mark me brainliest if I'm right :)

4 0
2 years ago
(x^2y^3) = (xy^a)^b
Rainbow [258]

Answer:

C. \frac{3}{2}

Step-by-step explanation:

To find the value f b, we need to compare the exponents.

The given exponential equation is:

( {x}^{2}  {y}^{3} )^{3}  = ( {x}  {y}^{a} )^{b}

Recall and apply the following rule of exponents.

( {x}^{m}  )^{n}  = {x}^{mn}

We apply this rule on both sides to get:

{x}^{2 \times 3}  {y}^{3 \times 3} =   {x}^{b}  {y}^{ab}

Simplify the exponents on the left.

{x}^{6}  {y}^{9} =   {x}^{b}  {y}^{ab}

Comparing exponents of the same variables on both sides,

b = 6 \: and \:\: ab = 9

\implies \: 6b = 9

Divide both sides by 6.

b =  \frac{9}{6}

b =  \frac{3}{2}

4 0
3 years ago
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