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Murljashka [212]
3 years ago
8

Find the difference (x^2+3y-3)-(-2x^2+3y-1)

Mathematics
2 answers:
Sedbober [7]3 years ago
8 0
The answer is 3x^2 - 2.

x^2+3y-3+2x^2-3y+1

Add the like terms together, you get 3x^2 - 2

Alexeev081 [22]3 years ago
8 0
X^2+3y-3+2x^2-3y+1

3x^2-2
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PLEASE HELP ME ASAP!!!!!!!
Alex777 [14]

Answer:

the answer is c

Step-by-step explanation:

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8 0
3 years ago
HELP ME ASAP!!!!!!!!!!!Choose the expression that best represents the phrase below. ...16 times as many books... A. 16 b B. 16 +
Ahat [919]

Answer: 16b


Step-by-step explanation:

1. You have the following phrase given in the problem: 16 times as many books. You can conclude this is a multiplication word problem, because:

- Let's call b the number of books.

- "As many boooks" indicates multiplication.

- 16 times means that b should be multiplied by 16.

2. Then, you can conclude that the expression that best represent the phrase is:

16b



6 0
4 years ago
Find the mean, median, and mode(s) of the data. Do not round. 2, 8, 10, 12, 56, 9, 5, 2, 4
Mariana [72]
The mean is 12, the median is 8, and the mode is 2.
8 0
3 years ago
Read 2 more answers
PLEASE HELP
Anit [1.1K]

Answer:

A\approx2.255 \text{ grams}

Step-by-step explanation:

We will use the standard formula for half-life:  

\displaystyle A=A_0(a)^\frac{t}{d}

Where A₀ is the initial amount, a is the half-life, d is the time for one half-life, and t is the number of days.

So, we will substitute 1/2 for a and 24.3 for d. This yields:

\displaystyle A=A_0(\frac{1}{2})^\frac{t}{24.3}

We have a 3 gram sample. Therefore, our initial amount A₀ is 3:

\displaystyle A=(3)(\frac{1}{2})^\frac{t}{24.3}

And we want to find the remaining sample after 10 days. So, t=10. Substitute:

\displaystyle A=(3)(\frac{1}{2})^\frac{10}{24.3}

Use a calculator. So:

A\approx2.255 \text{ grams}

Therefore, for a 3 gram sample of Phosphorous-32 with a half-life of 24.3 days, after 10 days, there will be approximately 2.255 grams remaining.

6 0
3 years ago
What is the slope of a trend line that passes through the points (–3, 3) and (18, 26)?
Tasya [4]
Use can you slope formula: 

\frac{Y_2 - Y_1 }{X_2 - X_1} 

Then, substitute values into the formula.

\frac{26 - 3}{18 - (-3)}

Then solve. You get the fraction, \frac{23}{21}. That is your slope. 


4 0
3 years ago
Read 2 more answers
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