Answer:
This cannot be solved unless I have the coordinate for triangle "abc"
Step-by-step explanation:
Once I have the coordinates for triangle "abc", I can solve to find out where triangle "A'B'C" is
Use Pythagorean theorem.
[tex]|ON|^2+|MN|^2=|OM|^2\\\\x^2+x^2=8^2\\\\2x^2=64\ \ \ \ |divide\ both\ sides\ by\ 2\\\\x^2=32\to x=\sqrt{32}\\\\x=\sqrt{16\cdot2}\\\\x=\sqrt{16}\cdot\sqrt2\\\\\boxed{x=4\sqrt2}
Answer: |MN| = 4√2.
Answer:
Lies in the shaded regions of both the top and bottom inequalities.
Step-by-step explanation:
The point of solution for BOTH systems of inequalities must work for both equations. Therefore, the point has to lie in both top and bottom shaded regions or it won't work for both, but just one.
Answer:
x ≥ 15
Step-by-step explanation:
200 + 20x ≥ 500
To solve this inequality, you must first subtract 200 from 500.
500 - 200 = 300.
Lastly, divide 300 by 20.
20x = 300
300 ÷ 20 = 15
Therefore, the value of x is 15.
