Question

FIND THE SOLUTION OF EACH EQUATION IF THE REPLACEMENT SETS ARE

Answer 1

1) There are no solutions for this equation in the solution set. 

2) The solution set is {5} because 15/5 = 3 

3) The solution set is {8} because
$31 = 3 (8) + 7 \\ 31 = 24 + 7 \\ 31 = 31$ 

4) The solution set is {20} because 20 - 13 = 7 

5) The solution set is {66} because 22 x 3 = 66 

6)
$A = 32 - 9(2) \\ A = 32 - 18\\ A = 14$ 

7)
$12 \times \frac{5}{15} - 3 = Y \\\\ 12 \times \frac{1}{3} -3 = Y \\\\ 4 -3 = Y \\ Y =1$ 

8) 
$27 + \frac{5}{16} = G\\\\G = \frac{432 + 5}{16}\\\\G = \frac{437}{16}\\\\G = 27 \frac{5}{16}$

9) 
$R = \frac{9(6)}{ ( 8 + 1 ) 3}\\\\R = \frac{54}{9(3)} \\\\R = \frac{54}{27}\\\\ R = 2$

10) 
$15,579 + 6,220 + 18,995 = G\\\\ G = 40,794$

11) The solution set is {6, 7} because:
 6 -2 < 6, which is 4 < 6
AND
7 - 2 < 6, which is 5 < 6

12) The solution set is {9, 11} because:
3 ≥ 25/9, which is 3 ≥ 2.77777777778
AND
3 ≥ 25/11, which is 3 ≥ 2.2727272727

Hope this helps :D