Establish two right triangles, both with the height of the pole, h.
Call x the distance from the pole to one stake. Then the distance from the other stake to the pole is 6 -x.
Apply Pytagora's equation to both triangles.
1) h^2 = 7^2 - x^2
2) h^2 = 8^2 - (6-x)^2
Eaual 1 to 2
7^2 - x^2 = 8^2 - 6^2 +12x -x^2
12x = 7^2 -8^2 +6^2 = 49 -64 + 36 = 21
x = 1.75
Substitue x-value in 1
h^2 = 49 - (1.75)^2 = 45.94
h = sqrt(45.94) = 6.78
Answer: option d.
Answer:
hey
Step-by-step explanation:
yep
a=3
a6=43
a+6d=43---------1
substituting a=3 in eq 1
a+6d=43
3+6d=43
6d=43-3
d=40/6
d=20/3
so first 5 no's are a, a+d, a2+d,a3+d, a4+d
a=3
a+d=3+20/d
i think u know after this
Hope it helps u
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