Sent a picture of the solution to the problem (s).
Answer:
x=−2
Step-by-step explanation: Step 1: Simplify both sides of the equation.
3(x−5)−3=5(x−2)+2x
(3)(x)+(3)(−5)+−3=(5)(x)+(5)(−2)+2x(Distribute)
3x+−15+−3=5x+−10+2x
(3x)+(−15+−3)=(5x+2x)+(−10)(Combine Like Terms)
3x+−18=7x+−10
3x−18=7x−10
Step 2: Subtract 7x from both sides.
3x−18−7x=7x−10−7x
−4x−18=−10
Step 3: Add 18 to both sides.
−4x−18+18=−10+18
−4x=8
Step 4: Divide both sides by -4.
−4x
−4
=
8
−4
x=−2
Answer:
a
Step-by-step explanation:
If

then

The ODE in terms of these series is



We can solve the recurrence exactly by substitution:


So the ODE has solution

which you may recognize as the power series of the exponential function. Then

You've given us a single term of an arithmetic series. So far, there are an infinite number of different series that it could be a member of. ... In fact, ANY function f (n) for which f (7) = 54 produces a suitable series for whole-number values of 'n'. Here are a few: ... T(n) = n + 47. ... T (n) = 8n - 2. ... T (n) = -10n + 124 .