Ask question

Ask question

All categories

3 years ago

13

Find the volume of the cylinder. r = 5 cm h = 9 cm

1 answer:

kvasek [131]3 years ago

5 0

Answer:

About 706.5 or 707

Explanation:

3.14 • 5² (5² is also 25) = 78.5

78.5 • 9 = 706.5 or 707

Edit: Also posted a better picture for explanation. See the attachment.

You might be interested in

an hourglass is turned over with the top part filled with sand. after 3 minutes, there are 855 ml of sand in the top half. after

Hitman42 [59]

An hourglass is turned over with the top part filled with sand. after 3 minutes, there are 855 ml of sand in the top half. after 10 minutes, there are 750 ml of sand in the top half. This can be represents a two points ( 3, 855) and (10, 750) . using this to solve the slope m = (750-855)/(10-3) = -15. And using one point the equation is y = -15x + 900.

5 0

3 years ago

Read 2 more answers

A space telescope on a mountaintop is housed inside of a cylindrical building with a hemispheric dome. If the circumference of t

Vlad1618 [11]

Answer:

$185553.7\text{ feet}^3$

Step-by-step explanation:

GIVEN: A space telescope on a mountaintop is housed inside of a cylindrical building with a hemispheric dome. If the circumference of the dome is $84\text{ feet}$ , and the total height of the building up to the top of the dome is $91\text{ feet}$ .

TO FIND: what is the approximate total volume of the building.

SOLUTION:

let the height of the mountaintop be $h\text{ feet}$

As the dome hemispherical.

circumference of a hemisphere $=\frac{1}{2}\times2\pi\times radius$

$=\pi\times radius$

$\frac{22}{7}\times radius=84$

$radius=26.75\text{ feet}$

total height of the building up to the top of the dome $=\text{radius of hemisphere}+\text{height of mountaintop}$

$=26.75+h=91$

$h=64.25\text{ feet}$

Volume of building $=\text{volume of cylindrical mountaintop}+\text{volume of dome}$

$=\pi(radius)^2h+\frac{2}{3}\pi(radius)^3$

as radius of mountain top is same as dome

putting values

$=3.14(26.75)^264.75+\frac{2}{3}3.14(26.75)^3$

$=145484.6+40069.1$

$185553.7\text{ feet}^3$

Hence the total volume of the building is $185553.7\text{ feet}^3$

5 0

3 years ago

A ship leaves port at 1:00 P.M. and travels S35°E at the rate of 27 mi/hr. Another ship leaves the same port at 1:30 P.M. and tr

Len [333]

To solve this problem you must apply the proccedure shown below:

1. You must apply the Law of Cosines, as you can see in the figure attached. Then:

- The first ship travels at $27 mi/hr$ in for two hours. Therefore, the side $a$ is:

$a=(27 mi/hr)(2 hr)=54mi$

- The second ship travels at $18 mi/hr$ for $1.5 hours$ . Therefore, the side $b$ is:

$b=(18mi/hr)(1.5hr)=27mi$

- Now, you can calculate $c$ :

$c=\sqrt{54^{2}+27^{2}-2(54)(27)Cos(55)}=44 mi$

The answer is: $44 miles$

8 0

3 years ago

True/False: Money that is usable can be easily moved from your home to the store.

egoroff_w [7]

Answer:

true

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Helpp me asapp with this problem plss will crown brainiest !!!!

Evgen [1.6K]

Answer:

see below

Step-by-step explanation:

Since RT bisects QRS

1/2 QRS = TRS

1/2 ( 9x+214) = -9x+53

Multiply each side by 2

9x +214 = -18x+ 106

Add 18x from each side

9x +214+18x = 106

27x +214 = 106

Subtract 214 from each side

27x = 106-214

27x =-108

Divide by 27

27x/27 = -108/27

x = -4

TRS = -9x+53

=-9 *-4 +53

= 36+ 53

=89

4 0

3 years ago

Read 2 more answers