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Alja [10]
4 years ago
14

-36 4/9 - (-10 2/9) -(18 2/9)

Mathematics
1 answer:
Degger [83]4 years ago
8 0

Answer: -44\dfrac{4}{9}

Step-by-step explanation:

The given expression: -36\dfrac{4}{9}-(-10\dfrac{2}{9})-(18\dfrac{2}{9})

Here, 36\dfrac{4}{9}=\dfrac{36\times9+4}{9}=\dfrac{328}{9}

(10\dfrac{2}{9})=\dfrac{92}{9}\\\\(18\dfrac{2}{9})=\dfrac{9\times18+2}{9}=\dfrac{164}{9}

That is

-36(\dfrac{4}{9})-(-10\dfrac{2}{9})-(18\dfrac{2}{9}) = -\dfrac{328}{9}-(-\dfrac{92}{9})-\dfrac{164}{9}\\\\=-\dfrac{328}{9}+\dfrac{92}{9}-\dfrac{164}{9}\\\\=\dfrac{-328+92-164}{9}\\\\=\dfrac{-400}{9}\\\\=-44\dfrac{4}{9}

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find three numbers whos sum is 86, if the first number is three times the difference between the second and the third, and the s
agasfer [191]

Answer: 45,28,13

Step-by-step explanation:


Firstly let’s call integer 3

‘x’

Following the information given the following equations can be constructed:

integer 3 = x


integer 2 = 2+2x because 2x represents 2 times integer 3 (which is x) and plus two

integer 1 =3((2x+2)-x) what we have written is the difference between integer 2 (which was (2x+2)) and integer 3 which was x and simply multiply the result of that subtraction by 3


next we can treat them like their own variables almost.

integer 1 + integer 2 + integer 3 =86


so now plug in the equations we have constructed for each integer:


(3((2x+2)-x)) + (2x+2) + x = 86


to make it easier to read please see the image attached below to solve for x


After you have gone through the image I have included you should notice x= 13 great we got one integer! (Integer 3)


now plug in 13 into our integer equations :


integer 2: 2(13)+2= 28

Therefore integer 2 is 28


integer 1: 3((2(13)+2)-(13))=
3((28-13)

3(15)

45

Therefore integer 1 is 45.


and integer 3 is x which as we now know is equal to 13

3 0
3 years ago
Show your work for factoring or quadratic formula:
lutik1710 [3]
First, I'd simplify this problem by dividing every term by 2:

x^4 - 4x^3 + 5x^2 - 4x + 4 = 0

Then I'd think of the possible factors of that constant term, 4:  They would be plus or minus 1, plus or minus 2, or plus or minus 4.

Let's try x = -4 as a possible root.  Setting up and using synthetic division:

      ____________________
-4  /   1   -4   5    -4    4
              -4   32
     ----------------------------
         1    -8  37

This result is not helpful.  So, try the possible root +4 instead:
       ________________
+4  /   1   -4   5    -4    4
                4    0   20   64
       ----------------------------
         1     0    5    16   68             4 is not a root because the remainder   
                                                    (68) is not zero.

Try x = 2:

       ________________
+2  /   1   -4   5    -4    4
                2   -4    2    -40
       ----------------------------
          1    -2   1    -2    0

2 is a root because the remainder is zero.

Continue this process until you've found the other 3 roots.

Hint:  Try  the possible root x = -2 with the following coefficients:

     ____________
-2 /  1   -2   1   -2

    ---------------------
5 0
3 years ago
What's 137 and h as an algebraic expression PLEASE HELP
lesya692 [45]

Answer:

137+h

Step-by-step explanation:

3 0
3 years ago
Can someone help me with this
Daniel [21]
Something below 4.70. Ex.. 4.69..
6 0
4 years ago
Read 2 more answers
PLZZ HELP ASAP ON 1 AND 2.a. AND 2.b.
dlinn [17]
Kind of a mess but let me know if you want me to explain more

6 0
3 years ago
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