All categories

3 years ago

The man is 6 feet tall. His shadow is 14 feet long. The tree's shadow is 49 feet long. Find the tree's height.

Mathematics

2 answers:

Tatiana [17]3 years ago

6 0

Answer:

21 ft

Step-by-step explanation:

Dmitry_Shevchenko [17]3 years ago

6 0

Answer:

21 feet

Step-by-step explanation:

You might be interested in

Matthew earned $75 in interest on

tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

The formula for simple interest is

I = Prt,

where I is the interest earned,

P is the initial investment amount,

r is the interest rate in decimal form, and

t is the time in years. For us,

I = 75,

P = ?

r = .05

t = 1

Filling in what we were given:

75 = P(.05)(1) and

.05P = 75 so

P = 1500

8 0

3 years ago

9c + 5a + 5a + b<br> Kssjjdkdd

Troyanec [42]

Answer:

10a+b+9c

Step-by-step explanation:

first you have to join the like terms then you add them then you write the answer, I hope you understood

9c+5a+5a+b

9c+10a+b

10a+b+9c

6 0

2 years ago

Read 2 more answers

One gallon of paint will cover 400 square feet. How many gallons of paint are needed to cover a wall that is 8 feet high and 100

juin [17]

The wall has an area of 8 * 100 = 800 square feet
So therefore 800/400 = 2 gallons are required the answer is C

3 0

3 years ago

Read 2 more answers

F(x, y, z) = yzexzi + exzj + xyexzk,

Ghella [55]

$\nabla f(x,y,z)=\mathbf F(x,y,z)\iff\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j+\dfrac{\partial f}{\partial z}\,\mathbf k=yze^{xz}\,\mathbf i+e^{xz}\,\mathbf j+xye^{xz}\,\mathbf k$

$\dfrac{\partial f}{\partial x}=yze^{xz}$
$\implies f(x,y,z)=\dfrac{yz}ze^{xz}+g(y,z)=ye^{xz}+g(y,z)$

$\dfrac{\partial f}{\partial y}=e^{xz}=e^{xz}+\dfrac{\partial g}{\partial y}$
$\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)$

$\dfrac{\partial f}{\partial z}=xye^{xz}=xye^{xz}+\dfrac{\mathrm dh}{\mathrm dz}$
$\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C$

$f(x,y,z)=ye^{xz}+C$

$\mathbf r(t)=(t^2+5)\,\mathbf i+(t^2-1)\,\mathbf j+(t^2-5)\,\mathbf k$
$\implies\mathbf r(0)=5\,\mathbf i-\mathbf j-5\,\mathbf k$
$\implies\mathbf r(5)=30\,\mathbf i+24\,\mathbf j+20\,\mathbf k$

By the gradient theorem, we have for any path $\mathcal C$ originating at the point (5, -1, -5) and terminating at the point (30, 24, 20),

$\displaystyle\int_{\mathcal C}\mathbf F\cdot\mathrm d\mathbf r=f(\mathbf r(5))-f(\mathbf r(0))=f(30,24,20)-f(5,-1,-5)$
$\implies\displaystyle\int_{\mathcal C}\mathbf F\cdot\mathrm d\mathbf r=24e^{600}+e^{-25}$

4 0

3 years ago

Determine whether each pair of segments is congruent

OLga [1]

Set XY = XZ and solve for x
3x+5 = 5x-1
6=2x
x = 3
Then XY = 14 and XZ = 14 and YZ = 13.5
XY congruent XZ

7 0

3 years ago

Read 2 more answers