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3 years ago

Find the surface area of the sphere with the given dimension. Leave your answer in terms of pi

Mathematics

1 answer:

alisha [4.7K]3 years ago

5 0

The answer is a............

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Can some0ne help me?

PtichkaEL [24]

Answer:

(x - 2)/3

(x - 4)/-5 or (-x + 4)/5

Step-by-step explanation:

this is an inverse function, and to solve an inverse function you would :

swap x and g(x) without bringing the x coefficient with it, just simply swap the variables. Then, solve for g(x), and that's it

the first question's answer is :

g(x) = 3x + 2

x = 3(g(x)) + 2

x - 2 = 3(g(x))

(x - 2)/3 = g(x)

the second one is:

g(x) = 4 - 5x

x = 4 - 5(g(x))

x - 4 = -5(g(x))

(x-4)/-5 = g(x)

4 0

3 years ago

Read 2 more answers

What is 1200 x 1200? (this is just becouse i was bored) Plz answer me thx

lawyer [7]

Answer:

$\tt{}1.440.000 \\$

Step-by-step explanation:

$\tt{}1.200 \times 1.200 \: \: \: \: \: \: \: \: \: \: \\ \\ \tt{}((12 \times 12) + (0000)) \\ \\ 1.440.000 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \\$

3 0

2 years ago

Evaluate 2(N + 3) if n = 5 show your work

algol [13]

ANSWER:

N = 16

STEP BY STEP EXPLANATION:

2(5+3)

n=16

6 0

3 years ago

Can someone awnser this

Ostrovityanka [42]

It has a constant daily growth rate of 1.5

5 0

3 years ago

Write the standard form of the equation of the circle that passes through the point

AnnZ [28]

Answer:

The standard form of the equation of the circle is $x^2+y^2=1$ .

Step-by-step explanation:

A circle is the set of points in a plane that lie a fixed distance, called the radius, from any point, called the center.

The equation of a circle in standard form is

$(x-h)^2+(y-k)^2=r^2$

where r is the radius of the circle, and h, k are the coordinates of its center.

When the center of the circle coincides with the origin $h=k=0$ , so

$(x-0)^2+(y-0)^2=r^2\\x^2+y^2=r^2$

We are also told that the circle contains the point (0, 1), so we will use that information to find the radius r.

$0^2+1^2=r^2\\r^2=0^2+1^2\\r^2=1\\r=\sqrt{1}$

Therefore, the standard form of the equation of the circle is $x^2+y^2=1$ .

5 0

3 years ago