Using the information given above, the sampling distribution of the sample proportion of 100-ohm gold-band is 2.
- <em>Sampling distribution of proportion, P = 2% = 0.02 </em>
- <em>Sample size, n = 100</em>
<u>The sampling distribution of the sample proportion can be calculated thus</u>:
- <em>Distribution of sample proportion = np</em>
Distribution of sample proportion = (100 × 0.02) = 2
Therefore, there is a probability that only 2 of the samples will have resistances exceeding 105 ohms.
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Answer:
x=2.5
Step-by-step explanation:
Answer:
1 17/24
Step-by-step explanation:
To add fractions, find the LCD and then combine.
Exact Form:
41/24
Decimal Form:
1.7083
Mixed Number Form:
1 17/24
Answer:
Me and my massive brain, among other massive things of mine, believe it to be -1
Step-by-step explanation:
Answer:
<h2>
x = 16 degrees</h2>
Step-by-step explanation:
1 and 3 are <u>vertical angles</u> so m∠1 = m∠3
(4x - 2)° = 62°
4x - 2 = 62
4x = 64
x = 16