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Komok [63]
2 years ago
7

What is the area of a circle that has circumference of 42 inches

Mathematics
1 answer:
mixer [17]2 years ago
7 0
I think the area of a circle with a circumference of forty two inches is
140.37 in^2
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Answer:

7-3.182 \frac{13.638}{\sqrt{4}}= -14.698

7+3.182 \frac{13.638}{\sqrt{4}}= 28.698

Step-by-step explanation:

For this case we have the following info given:

Weight before diet 180 125 240 150  

Weight after diet 170 130 215 152

We define the random variable D = before-after and we can calculate the inidividual values:

D: 10, -5, 25, -2

And we can calculate the mean with this formula:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

And the deviation with:

s= \sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

And after replace we got:

\bar D= 7, s_d = 13.638

And the confidence interval for this case would be given by:

\bar D \pm t_{\alpha/2} \frac{s_d}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1= 4-1=3

For the 95% of confidence the value for the significance is \alpha=0.05 and the critical value would be t_{\alpha/2}= 3.182. And replacing we got:

7-3.182 \frac{13.638}{\sqrt{4}}= -14.698

7+3.182 \frac{13.638}{\sqrt{4}}= 28.698

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