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3 years ago

The area of circle z is 64 pi ft^2 What is the value of r?

Mathematics

2 answers:

vampirchik [111]3 years ago

7 0

we know that

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

In this problem we have

$A=64\pi \ ft^{2}$

substitute in the formula and solve for r

$64\pi=\pi r^{2}$

Simplify

$64=r^{2}$

Square root both sides

$r=8\ ft$

therefore

the answer is

The value of r is $8\ ft$

erica [24]3 years ago

6 0

To find area of a circle, one must perform the equation "pi(r)^2" we have all information but the radius which has become inclusive in the question. To draw out the radius, all you gotta do is defuse 64 into its square root-8. The radius is 8.

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Elizabeth lives in San Francisco and works in Mountain View. In the morning, she has 3 transportation options (take a bus, a cab

Lesechka [4]

Answer:

4/9

Step-by-step explanation:

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3 years ago

Not good with fractions can you help me out here. 8y =5

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: midpoints between AP QB

Digiron [165]

Answer: The distace between midpoints of AP and QB is $\frac{a}{8}$ .

Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:

AP + PQ + QB = a

According to the question, AP = 2 PQ = 2QB, so:

PQ = $\frac{AP}{2}$

QB = $\frac{AP}{2}$

Substituing:

AP + 2*( $\frac{AP}{2}$ ) = a

2AP = a

AP = $\frac{a}{2}$

Since the distance is between midpoints of AP and QB:

2QB = AP

QB = $\frac{AP}{2}$

QB = $\frac{a}{2}*\frac{1}{2}$

QB = $\frac{a}{4}$

MIdpoint is the point that divides the segment in half, so:

Midpoint of AP:

$\frac{AP}{2} = \frac{a}{2}*\frac{1}{2}$

$\frac{AP}{2} = \frac{a}{4}$

Midpoint of QB:

$\frac{QB}{2} = \frac{a}{4}*\frac{1}{2}$

$\frac{QB}{2} = \frac{a}{8}$

The distance is:

d = $\frac{a}{4} - \frac{a}{8}$

d = $\frac{a}{8}$

4 0

2 years ago

For what value of x is (2x^2+8x)/(x+4)(x^2-9) undefined?

irakobra [83]

Answer:

The value at x =3 is undefined for the given expression

Step-by-step explanation:

Given expression is $\frac{2x^2+8x}{(x+4)(x^2-9)}$

To find for what value of x is undefined in the given expression :

$\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x(x+4)}{(x+4)(x^2-9)}$

$=\frac{2x}{x^2-9}$

$\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x}{x^2-9}$

If we put x=3 in the above expression we get

$\frac{2x}{x^2-9)}=\frac{2(3)}{3^2-9}$

$=\frac{6}{9-9}$

$=\frac{6}{0}$

Therefore $\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{6}{0}$

The value at x =3 is undefined for the given expression

7 0

3 years ago

I need answer To number 32-34 i need This done by Tuesday

BaLLatris [955]

34 is Y=56 that why he stay with 101 at the end.

4 0

3 years ago