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madreJ [45]
3 years ago
8

1.) You decide to order strands of LED lights for a party. Amazon charges

Mathematics
1 answer:
Vikki [24]3 years ago
6 0

Answer:

11

Step-by-step explanation:

56.50-7=49.50

49.50divided by 4.50=11

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16 increased by twice a number is -24 what is the solution?
Lynna [10]

Let x = the number.

"increased by" tells you we are adding.

"twice a number" tells you 2 times a number.

16 + 2x = - 24

Subtract 16 from both sides so that we have the variable on one sides and the constants on the other.

2x = - 24 - 16

2x = - 40

Divide by 2 to isolate the variable.

x = - 40/2 = - 20

Your solution is - 20.

To check your answer, plug in.

16 + 2(-20) = - 24

16 - 40 = - 24

- 24 = - 24

3 0
3 years ago
Marty has 1/2 pound of raisins to divide equally into 10 different bags. What fraction of a pound will be in each bag?
aivan3 [116]
10/8 = 1.25 oz.

there are 8 ounces in 1/2 of a pound.  if you divide 8 by 10 bags it equals 1.25 ounces in each bag
8 0
3 years ago
Am I correct? Please explain!<br><br> Will mark brainliest
marta [7]

Answer:

nr. 1 and 3 is a Dilation 2 and 4 are not Dilations

Step-by-step explanation:

Dilation is an elnargment or shink of a figure by a x(factor) that makes the SAME image but smaller or larger

4 0
3 years ago
The table shows the circumference of a tree in centimeters, y, at 2 years.
kati45 [8]

Answer:b

Step-by-step explanation:

6 0
3 years ago
According to the United States Health and Human Services, the mean height for Americans is 1.757 meters for men and 1.618 meters
Alchen [17]

Answer:

Her z-score is 2.03.

Step-by-step explanation:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

Michelle’s height is 1.758 meters. What is her z-score?

Michelle's is a woman.

The average height of women is \mu = 1.618 and the standard deviation is \sigma = 0.069

This is Z when X = 1.758. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.758 - 1.618}{0.069}

Z = 2.03

Her z-score is 2.03.

7 0
3 years ago
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