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3 years ago

3/10 1/2 common denominator

Mathematics

2 answers:

uranmaximum [27]3 years ago

5 0

3/10 and 5/10

Hope this helps!

Ugo [173]3 years ago

4 0

Answer:

3/10 and 5/10

Step-by-step explanation:

can i get the crown plz

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What is the solution to this equation y=4x (1,3) (-1,-4) (-4,-1) (1,-4) !ASAP!

RideAnS [48]

(-1,-4) this is saying that when x=-1, y=-4. Plugging it into the line equation y=4x gives
$(- 4) = 4( - 1)$
Which is correct.

3 0

3 years ago

What is the value of e^3x+6=8

Natasha2012 [34]

Hello there!

Answer: ⇒⇒ $x=\frac{2}{e^3}$

___________________________________________________

Step-by-step explanation:

First you had to subtract by 6 from both sides of equation.

$e^3x+6-6=8-6$

Simplify.

$e^3x=2$

Then you divide by e³ from both sides of equation.

$\frac{e^3x}{e^3}=\frac{2}{e^3}$

Simplify it should be the correct answer.

$x=\frac{2}{e^3}$

____________________________________________________________

Hope this helps!

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Have a great day!

-Charlie

4 0

3 years ago

Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find

Papessa [141]

Answer:

1) $\text{P(at least one boy and one girl)}=\frac{3}{4}$

2) $\text{P(at least one boy and one girl)}=\frac{3}{8}$

3) $\text{P(at least two girls)}=\frac{1}{2}$

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To Find : The probability of each event.

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

1) P(at least one boy and one girl)

Favorable outcome = BBG, BGB, BGG, GBB, GBG, GGB=6

$\text{P(at least one boy and one girl)}=\frac{6}{8}$

$\text{P(at least one boy and one girl)}=\frac{3}{4}$

2) P(at least one boy and one girl)

Favorable outcome = BBG, BGB, GBB=3

$\text{P(at least one boy and one girl)}=\frac{3}{8}$

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

$\text{P(at least two girls)}=\frac{4}{8}$

$\text{P(at least two girls)}=\frac{1}{2}$

4 0

4 years ago

Read 2 more answers

Joe works at YummyBurger. He earns a salary of $50 a day plus $0.05 for every super-sized value meal he sells. Nate works at Sup

Brums [2.3K]

Answer:

300 burgers

Step-by-step explanation:

You can set up an equation like this: 50+0.05x=20+0.15x

Then, subtract 0.05x from both sides: 50=20+0.10x

Subtract 20 from both sides: 30=0.10x

Divide by .10 on both sides: 300=x

X represents how many burgers must be sold for the boys to have earned the same amount of money, and that is 300 burgers.

7 0

4 years ago

Read 2 more answers

Easy 7th grade pre algebra! Help!

Naddik [55]

Statement A is the false one.

7 0

3 years ago

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