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2 years ago

Two balls are drawn in succession out of a box containing

1 answer:

4 0

There are a total of 8 balls

The probability of drawing a white ball is 4/8 on the first draw.
If you replace the ball then the probability will still be 4/8 for a white ball, since these events are independent of each other you multiply 4/8 x 4/8 = 16/64 or 1/4 then the probability of drawing at least 1 red ball with replacement is 1 - 1/4 = 3/4

Now without replacement:
the probability of drawing a white ball is 4/8 since you don't replace the ball then the probability of drawing a white ball the second time is 3/7 again multiply these two probabilities: 4/8 x 3/7 = 12/56 the the probability of drawing at least 1 red ball is 1- 12/56 = 44/56 or 11/14

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Emma uses a 250 meter roll of creep paper to make streamers how many decameters of Crete paper does Emma have

8090 [49]

Well a decameter is 10 meters so if she has 250 meters then she has 25 decameters Hope this helps!

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3 years ago

What a deal! Just deShirts is having a 20% off sale. Trixie rushes to the store and buys 14 shirts. When the clerk rings up her

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2 years ago

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vagabundo [1.1K]

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2 years ago

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Which sequence of transformations will only produce a figure similar to but not congruent to the figure ABCD

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A dialation is the answer.

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2 years ago

PLEASE HELP ME WITH THIS QUESTION ITS URGENT!!!

Alex Ar [27]

Start by distributing the exponent to each of the terms in $(2u)^{3}$ . This will become $2^{3} u^{3}$ , and $2^{3} =8$ . Now, the expression is:

$\frac{2u^{3} v^{2} }{8u^{3} * u^{2} }$ .

We can now simplify the bottom to read: $8u^{5}$ because when multiplying variables raised to an exponent, we add the exponents. The expression now looks like:

$\frac{2u^{3} v^{2} }{8u^{5} }$

The 2/8 simplifies to 1/4:

$\frac{u^{3} v^{2} }{4u^{5} }$

Now, we have two u terms on the top and bottom. When dividing variables raised to an exponent, we subtract the exponents. However, since 3-5=-2, the term will be on the bottom to avoid the negative exponent. The final answer is:

$\frac{v^{2} }{4u^{2} }$

Hope this makes sense!!

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3 years ago