Answer:
False
Step-by-step explanation:
We first write the equation in the form ax² + bx + c=0 which gives us:
3x² - 6x + 9=0
Given the quadratic formula,
x= [-b ±√(b²- 4ac)]/2a ,the discriminant proves whether the equation has real roots or not.
The discriminant, which is the value under the root sign, may either be positive, negative or zero.
Positive discriminant- the equation has two real roots
Negative discriminant- the equation has no real roots
Zero discriminant - The equation has two repeated roots.
In the provided equation, b²-4ac results into:
(-6)²- (4×3×9)
=36-108
= -72
The result is negative therefore the equation has no real solutions.
Answer:
<h2>
1/64</h2>
Step-by-step explanation:
just took the test and got 100% :)
Have a nice day!!
- <em> Shadow</em>
Answer:
Step-by-step explanation:
We have to find the equation of plane that is parallel to the vectors
The plane also passes through the point (2,0,-1).
Hence, the equation of plane s given by:
![\displaystyle\left[\begin{array}{ccc}x-2&y-0&z+1\\3&0&3\\0&1&3\end{array}\right]\\\\=(x-2)(0-3) - (y-0)(9-0) + (z+1)(3-0)\\=-3(x-2)-9y+3(z+1)\\\Rightarrow -3x + 6 - 9y + 3z + 3 = 0\\\Rightarrow 3x + 9y -3z -9 = 0\\\Rightarrow x + 3y -z - 3 = 0](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx-2%26y-0%26z%2B1%5C%5C3%260%263%5C%5C0%261%263%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%3D%28x-2%29%280-3%29%20-%20%28y-0%29%289-0%29%20%2B%20%28z%2B1%29%283-0%29%5C%5C%3D-3%28x-2%29-9y%2B3%28z%2B1%29%5C%5C%5CRightarrow%20-3x%20%2B%206%20-%209y%20%2B%203z%20%2B%203%20%3D%200%5C%5C%5CRightarrow%203x%20%2B%209y%20-3z%20-9%20%3D%200%5C%5C%5CRightarrow%20x%20%2B%203y%20-z%20-%203%20%3D%200)
It is the required equation of plane.
