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MrMuchimi
4 years ago
13

$43 shirt; 6% tax round to the nearest cent

Mathematics
2 answers:
timama [110]4 years ago
8 0
$43×(1+.06)= $45.58 which doesn't need to be rounded
Aleksandr-060686 [28]4 years ago
7 0
If you would like to know how much did the shirt cost after 6% tax, you can calculate this using the following steps:

6% of $43 = 6/100 * 43 = $2.58

$43 + $2.58 = $45.58

The correct result would be $45.58. 
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Step-by-step explanation:

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A large storage tank, open to the atmosphere at the top and filled with water, develops a small hole in its side at a point 10.4
vlabodo [156]

Answer:

Therefore the diameter of the hole is 1.94 \times 10^{-3} m.

Step-by-step explanation:

Bernoulli's equation,

P_1+\frac12 \rho v^2_1+\rho g h_1= P_2+\frac12 \rho v^2_2+\rho g h_2

P₁ = P₂= atmospheric presser

\rho= density

\frac12 \rho v^2_1+\rho g h_1= \frac12 \rho v^2_2+\rho g h_2             [since P₁ = P₂]

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\Rightarrow\frac12 v^2_2-\frac12 v^2_1=g h_1- g h_2

\Rightarrow v^2_2- v^2_1=2g h                                [h_1-h_2=h]

Here   v_1\approx 0

\Rightarrow v^2_2=2g h

\therefore v_2=\sqrt {2gh

Here g= 9.8 m/s² , h = 10.4 m

The velocity of water that leaves from the hole v_2 = \sqrt {2\times 9.8\times 10.4} m/s

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Given, the rate of flow from the leak is 2.53\times 10^{-3} m^3/min

                                                               =\frac{2.53\times 10^{-3}}{60}  m^3/s

Let the diameter of the hole be d.

Then the cross section area of the hole is =\pi (\frac d2)^2

We know that,

The rate of flow = Cross section area × speed

\Rightarrow \frac{2.53\times 10^{-3}}{60} =\pi (\frac d2)^2\times 14.28

\Rightarrow (\frac d2)^2=\frac{2.53\times 10^{-3}}{60\times 14.28\times \pi}

\Rightarrow d= 1.94 \times 10^{-3}

Therefore the diameter of the hole is 1.94 \times 10^{-3} m.

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Step-by-step explanation:

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