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Anna11 [10]
3 years ago
9

HELPP I NEED THIS ASAP!! 10 points

Mathematics
1 answer:
Veronika [31]3 years ago
4 0

Answer:

(∠C) ≅ (∠B)

∴ tan(∠B) = tan(∠C) and

Slope AB = Slope BC

Step-by-step explanation:

Part A:

To explain why the slope from point from A to B is the same with the slope from B to C with similar triangles we have;

The angle between segment AB and the vertical is the same as the angle between segment BC and the vertical - (corresponding angles)

The angle between segment AB and the horizontal is the same as the angle between segment BC and the horizontal - (corresponding angles)

The length of a segment opposite to the angle between segment AB and the horizontal is the as the length of a segment opposite to the angle between segment BC and the horizontal

Therefore, the triangle formed by A, B and the point of intersection of the vertical line from A with the horizontal line from B is congruent to the triangle formed by B, C and the point of intersection of the vertical line from B with the horizontal line from C

Which gives the angle with the horizontal at C (∠C) is congruent to the angle with horizontal B (∠B)

The slope AB = tan(∠B)

Slope BC = tan(∠C)

(∠C) ≅ (∠B)

Therefore, tan(∠B) = tan(∠C) and slope AB = Slope BC.

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<h2><em>Answer:</em></h2><h2><em>1</em><em>.</em><em>0</em><em>6</em></h2>

<em>Solution</em><em>,</em>

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<em>or,</em><em>9</em><em>x</em><em>=</em><em>1</em><em>5</em><em>(</em><em>7</em><em>-</em><em>6</em><em>x</em><em>)</em><em>[</em><em> </em><em>cross </em><em>multiplication]</em>

<em>or,</em><em>9</em><em>x</em><em>=</em><em>1</em><em>0</em><em>5</em><em>-</em><em>9</em><em>0</em><em>x</em>

<em>or,</em><em>9</em><em>x</em><em>+</em><em>9</em><em>0</em><em>x</em><em>=</em><em>1</em><em>0</em><em>5</em>

<em>or,</em><em>9</em><em>9</em><em>x</em><em>=</em><em>1</em><em>0</em><em>5</em>

<em>or,</em><em>X=</em><em>1</em><em>0</em><em>5</em><em>/</em><em>9</em>

<em>X=</em><em>1</em><em>.</em><em>0</em><em>6</em>

<em>Hope </em><em>it</em><em> helps</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

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