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bixtya [17]
3 years ago
7

A(-3, 9) and B(5, 9) are the endpoints of the diameter of a circle. Use these points to find the standard equation of the circle

.

Mathematics
1 answer:
aksik [14]3 years ago
7 0
Check the picture below.

notice the midpoint of the diameter segment, is just 1,9.

also, recall the radius is half the diameter, notice how long the radius is, just 4 units.

\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}\\
&1&9&4
\end{array}

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Write the equation of the ellipse with foci at (-2,2) and (4,2) and major axis of length 10 *
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Answer:

The answer to your question is   \frac{(x - 1)^{2}}{25} + \frac{(y - 2)^{2}}{16} = 1          

Step-by-step explanation:

Data

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Process

1.- Plot the foci to determine if the ellipse is vertical or horizontal. See the picture below.

From the graph we conclude that it is a horizontal ellipse.

2.- Determine the foci axis (distance between the foci)

                  2c = 6

                    c = 6/2

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3.- Determine a

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4.- Determine b using the Pythagorean theorem

                   a² = b² + c²

-Solve for b

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                   b² = 5² - 3²

                   b² = 25 - 9

                   b² = 16

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5.- Find the center (1, 2)  From the graph, it is in the middle of the foci

6.- Find the equation of the ellipse

                      \frac{(x - 1)^{2}}{5^{2}} + \frac{(y - 2)^{2}}{4^{2}} = 1

                       \frac{(x - 1)^{2}}{25} + \frac{(y - 2)^{2}}{16} = 1                

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