Answer:
Step-by-step explanation:
We want to write the trignometric expression:
As an algebraic equation.
First, we can focus on the inner expression. Let θ equal the expression:
Take the secant of both sides:
Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:
By substitutition:
Using an double-angle identity:
We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:
Simplify. Therefore:
The equation of a circle centred at point (m,n) and radius r is given by
<span>(x-m)² + (y-n)² = r²
</span>-------------------------------------------------------------
Centre = (4,3)
radius = 5
Equation:
(x - 4)² + (y - 3)² = 5²
⇒ x² - 8x + 16 + y² - 6y + 9 = 25
⇒ x² + y² - 8x - 6y + 25 = 25
⇒ x² + y² - 8x - 6y = 0
The equation of the circle is x² + y² - 8x - 6y = 0
Hope it helps!
Answer:
No, it's not
Step-by-step explanation:
Answer:
24
Step-by-step explanation:
area = wl (6×4 = 24)
w width l length
Answer:
1/63
Step-by-step explanation:
There are a couple of ways to do this.
<h3>1) </h3>
Look for the GCF of the numerators when a common denominator is used.
GCF(3/7, 4/9) = GCF(27/63, 28/63) = (1/63)·GCF(27, 28)
GCF(3/7, 4/9) = 1/63
__
<h3>2) </h3>
Use Euclid's algorithm. If the remainder from division of the larger by the smaller is zero, then the smaller is the GCF; otherwise, the remainder replaces the larger, and the algorithm repeats.
(4/9)/(3/7) = 1 remainder 1/63*
(3/7)/(1/63) = 27 remainder 0
The GCF is 1/63.
__
* The quotient is 28/27 = 1 +1/27 = 1 +(1/27)(3/7)/(3/7) = 1 +(1/63)/(3/7) or 1 with a remainder of 1/63.
_____
<em>Additional comment</em>
3/7 = (1/63) × 27
4/9 = (1/63) × 28
