Answer:
![\large\boxed{(x-8)^2+(y-6)^2=6^2\to(x-8)^2+(y-6)^2=36}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%28x-8%29%5E2%2B%28y-6%29%5E2%3D6%5E2%5Cto%28x-8%29%5E2%2B%28y-6%29%5E2%3D36%7D)
Step-by-step explanation:
The standard form of an equation of a circle:
![(x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
<em>(h, k)</em><em> - center</em>
<em>r</em><em> - radius</em>
We have the center (8, 6) → h = 8, k = 6,
and endpoints of a radius (8, 6) & (8, 0).
The formula of a distance between two points:
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Substitute:
![r=\sqrt{(0-6)^2+(8-8)^2}=\sqrt{(-6)^2+0^2}=\sqrt{36}=6](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B%280-6%29%5E2%2B%288-8%29%5E2%7D%3D%5Csqrt%7B%28-6%29%5E2%2B0%5E2%7D%3D%5Csqrt%7B36%7D%3D6)
Finally:
![(x-8)^2+(y-6)^2=6^2](https://tex.z-dn.net/?f=%28x-8%29%5E2%2B%28y-6%29%5E2%3D6%5E2)
Here’s the work to find the equation of the line.
for help with a graph, i suggest using the free graphing app (or website) desmos
Answer:
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