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Mashcka [7]
3 years ago
5

Amir pitches a baseball at an initial height of 6 feet, with a velocity of 73 feet per second. If the batter misses, about how l

ong does it take the ball hit the ground?
Hint: Use H(t) = -16t^2+vt+s
Mathematics
2 answers:
yarga [219]3 years ago
8 0

Answer:

4.643 seconds

Step-by-step explanation:

We have been given that

s = 6 feet

v = 73 feet per second

Substituting these values in the formula H(t)=-16t^2+vt+s

H(t)=-16t^2+73t+6

When the ball hits the ground, the height becomes zero. Thus, H(t)=0

-16t^2+73t+6=0

We solve the equation using quadratic formula x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Substituting the values a=-16,\:b=73,\:c=6

t_{1,\:2}=\frac{-73\pm \sqrt{73^2-4\left(-16\right)6}}{2\left(-16\right)}\\\\=\frac{-73\pm\sqrt{5713}}{-2\cdot \:16}\\\\=-0.081,4.643

time can't be negative. Hence, t = 4.643.

Hence, the ball will take  4.643 seconds to hit the ground.

JulijaS [17]3 years ago
6 0
Hey! The correct time is 4.64 seconds.
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Answer:

c = 40 and d = 76

Step-by-step explanation:

this is going to take me a long time to explain but here we go

so you need to do 180 - 116 and get 64.

then create a equation that is like this 7y + 6 + 4y + 64 = 180

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OLEGan [10]

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Step-by-step explanation:

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3 0
3 years ago
Please help it would be much appreciated.
yulyashka [42]
100
explanation: those two angles are supplementary which add up to be 180.
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faltersainse [42]

20% of 65 is 0.2 times 65 which is 13.

Hope this helps.

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