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3 years ago

I'm confused can someone help

Mathematics

1 answer:

Reil [10]3 years ago

5 0

Answer:

Step-by-step explanation:

a= 2 + 8 = 10

b = 10 - 4 = 6

So the answer is 7^6

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What is 2/5 ÷ 6/8 please

Alchen [17]

The First Answer is 0.4 and the second answer is 0.75.

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3 years ago

Read 2 more answers

Which expression can be used to find the surface area of the following rectangular prism?

sergeinik [125]

Answer:

It would be C.

Step-by-step explanation:

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4 years ago

Which of the following best describes the set of all numbers of the form a+bi where a and b are any real numbers and i equals sq

Andrei [34K]

<h3>Answer: B) Complex numbers</h3>

Complex numbers are always in the form a+bi with 'a' and 'b' as real numbers.

If b = 0 and 'a' is nonzero, then a+bi = a+0i = a which is strictly a real number

If a = 0 and b is nonzero, then a+bi = 0+bi = bi indicating that the number is now purely imaginary

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3 years ago

Okay so I have multiple questions that I need help with so I will put them below and you will get more points! Once you know the

lana66690 [7]

Vcylinder=hpir^2
Vcone=(1/3)hpir^2

d/2=r

so

1.
d=8
r=8/2=4
h=3r
h=3(4)
h=12
V=12*3.14*4^2
V=602.88 in^2

2. cone that fits has same base area and therefor same radius
d=6
r=6/2=3
rcone=3
find height of can
V=hpir^2
21=h*3.14*3^2
21=h*3.14*9
0.7431=h
so
cone height=0.7431
radius=3
V=(1/3)(0.7431)(3.14)(3^2)
V=7 cubic units

3.
same base
find dimentions
s=s=s
V=s^3
27=s^2
3=s
Vsquarepyramid=(1/3)hs^2
s=legnth of base
h=height
h=side
V=(1/3)(3)(3^2)
V=9
C

1. 602.88 in^2
2. 7 cubic units
3. 9cm^3, C

5 0

3 years ago

find the number of subsets of s = 1 2 3 . . . 10 that contain exactly 4 elements including 3 or 4 but not both.

Anna007 [38]

Answer:

112

Step-by-step explanation:

Let A be a subset of S that satisfies such condition.

If 3∈A, then the other three elements of A must be chosen from the set B={1,2,5,6,7,8,9,10} (because 3 cannot be chosen again and 4 can't be alongside 3). B has eight elements, then there are $\binom{8}{3}=56$ ways to select the remaining elements of A (the binomial coefficient counts this). The remaining elements determine A uniquely, then there are 56 subsets A.

If 4∉A, we have to choose the remaining elements of A from the set B={1,2,5,6,7,8,9,10}. B has eight elements, then there are $\binom{8}{3}=56$ ways to select the remaining elements of A. Thus, there are 56 choices for A.

By the sum rule, the total number of subsets is 56+56=112

4 0

4 years ago

I'm confused can someone help ​

I'm confused can someone help