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Ivenika [448]
4 years ago
8

terry drove 310 miles in 5 hours at a constant speed. how long would it take him to drive 403 miles at the same speed

Mathematics
1 answer:
laiz [17]4 years ago
6 0
Take 310 and divide it by 5 to get Miles per Hour then divide 403 by the number you found(should be 62) to get the amount of hours need to travel 403 miles. So altogether you do 310 divided by 5=62 then 403 divided by 62=6.5 hours to travel 403 miles.
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Simplify the following expression:<br> 3[(x^3– 7 x + 1) – (x+ 4)]
Alona [7]

Answer:

15 - 9

Step-by-step explanation:

3[( 3x - 7x plus 1) - (x plus 4)]

3[(-4x plus 1) - x-4

3[-4x plus 1 -x-4

3[-4x-x plus 1-4]

3[fivex -3]

fifteen x - 9

5 0
3 years ago
Solve 2^10 + 2^10 = 2^n.
Lina20 [59]

Answer: n = 11

Step-by-step explanation:

2^10 = 1,024

1,025 + 1,025 = 2,048

2^11 = 2,048

8 0
3 years ago
Read 2 more answers
Evaluate the expression when a=2 and b=20. 50a - 2b + 6 = [ ? ]​
masha68 [24]

Hey there! I'm happy to help!

Let's plug in the values for a and b.

50(2)-2(20)+6

If a number is next to the parentheses you multiply.

100-40+6

60+6

66

Have a wonderful day! :D

3 0
3 years ago
F(x)= square root of x+2; g(x)=8x-12<br> find f(g(x))
Ann [662]
f(x)=\sqrt{x+2}\\g(x)=8x-12\\f(g(x))=\sqrt{8x-12+2}=\sqrt{8x-10}

4 0
3 years ago
What are expressions for MN and LN? Hint Construct the altitude from M to LN.
Nikitich [7]

The question is missing the figure. So, it is in the atachment.

Answer: MN = x\sqrt{2}  LN = \frac{x}{2}.(\sqrt{2} + \sqrt{6} )

Step-by-step explanation: The first figure in the attachment is the figure of the question. The second figure is a way to respond this question by tracing the altitude from M to LN as suggested. When an altitude is drawn, it forms a 90° angle with the base, as shown in the drawing. To determine the other angle, you have to remember that all internal angles of a triangle sums up to 180°.

For the triangle <u>on the left</u> of the altitude:

45+90+angle=180

angle = 45

For the triangle <u>on the right</u>:

30+90+angle=180

angle = 60

With the angles, use the Law of Sines, which is relates sides and angles, as follows:

\frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

For MN:

\frac{x}{sin(30)} = \frac{MN}{sin(45)}

MN = \frac{x.sen(45)}{sen(30)}

MN = x\sqrt{2}

For LN:

\frac{LN}{sen(105)} =\frac{x}{sin(30)}

LN = \frac{x.sin(105)}{sin(30)}

We can determine sin (105) as:

sin(105) = sin(45+60)

sin(105) = sin(45)cos(60) + cos(45)sin(60)

sin(105) = \frac{\sqrt{2} }{2}.\frac{1}{2} + \frac{\sqrt{2} }{2}.\frac{\sqrt{3} }{2}

sin(105) = \frac{\sqrt{2} }{4} + \frac{\sqrt{6} }{4}

LN = \frac{x.sin(105)}{sin(30)}

LN = x.(\frac{\sqrt{2} }{4} + \frac{\sqrt{6} }{4}  ) .2

LN = \frac{x}{2}.(\sqrt{2} + \sqrt{6} )

The expressions for:

MN = x\sqrt{2}

LN = \frac{x}{2}.(\sqrt{2} + \sqrt{6} )

6 0
3 years ago
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