Last year, a person wrote 126 checks. Let the random variable x represent the number of checks he wrote in one day, and assume

Question

3 years ago

9

that it has a Poisson distribution. What is the mean number of checks written per day? What is the standard deviation? What is the variance?

1 answer:

Arisa [49] · Answer 1 · 2022-02-09T16:30:45+03:00

Answer: The mean number of checks written per day $=0.3452$

Standard deviation $=0.5875$

Variance $=0.3452$

Step-by-step explanation:

Given : The total number of checks wrote by person in a year = 126

Assume that the year is not a leap year.

Then 1 year = 365 days

Let the random variable x represent the number of checks he wrote in one day.

Then , the mean number of checks wrote by person each days id=s given by :-

$\lambda=\dfrac{126}{365}\approx0.3452$

Since , the distribution is Poisson distribution , then the variance must equal to the mean value i.e. $\sigma^2=\lambda=0.3452$

Standard deviation : $\sigma=\sqrt{0.3452}=0.5875372328\approx0.5875$

Last​ year, a person wrote 126 checks. Let the random variable x represent the number of checks he wrote in one​ day, and assume