For # 3 and 5 you need to use the quadratic formula:
<span>(-b +/- srt(b^2 - 4ac))/2a </span>
<span>a, b, and c are representative of this formula: ax^2 +bx + c </span>
<span>1) 2x^2+3x-9=0 </span>
<span>(2x - 3)(x + 3) = 0 </span>
<span>2x - 3 = 0, x + 3 = 0 </span>
<span>+3 +3, -3 -3 </span>
<span>2x = 3, ***x = -3*** </span>
<span>/2 /2 </span>
<span>***x = 3/2*** </span>
<span>2) 5x^2+2x=0 </span>
<span>(x)(5x + 2) = 0 </span>
<span>5x +2 = 0, ***x = 0*** </span>
<span>-2 -2 </span>
<span>5x = -2 </span>
<span>/5 /5 </span>
<span>***x = -2/5*** </span>
<span>4) 4x^2+7x-2=0 </span>
<span>(4x - 1)(x + 2) = 0 </span>
<span>4x - 1 = 0, x + 2 = 0 </span>
<span>+1 +1, -2 -2 </span>
<span>4x = 1, ***x = -2*** </span>
<span>/4 /4 </span>
<span>***x = 1/4***</span>
<span>an expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable(s).</span>
50 = 25 * 2 = 5 * 5 * 2
44 = 22 * 2 = 11 * 2 * 2
7b / 12 = 4.2
multiply both sides by 12
7b = 50.4
divide both sides by 7 to isolate b
b = 7.2
<em>Answer:</em>
47/48
<em>Explanation:</em>
Since 5 7/8 is so close to 6, it is easier to work this problem by considering the difference.
The serving size is 1/6 of the total amount, so you want to find ...
... (5 7/8) × (1/6)
Following the observation above, we can compute it as ...
... (6 - 1/8) × (1/6) = (6/6) - (1/8)×(1/6)
... = 1 - 1/48
... = <em>47/48</em>
